An element of evidence indicating that the color of the flame is attributed to the metal ion rather than the chemical is that none of the flames produced by different metals shared the same color (each metal produced its unique flame color). Although most tested metals had chloride, the flame colors were all distinct. The two flames that contained copper (one from copper (II) chloride and the other from copper (II) sulfate) showed similar colors; one was green-blue and the other was bright green. This suggests a close resemblance, and any slight variation could be attributed to error.
The energy released results in a kinetic energy of 92.2 keV for the products. We should convert keV into Joules, noting that 1 keV equals a kiloelectron volt. The required conversion is: 1.602×10⁻¹⁹ <span>joule = 1 eV
Kinetic energy = 92.2 keV * (1,000 eV/1 keV) * (</span>1.602×10⁻¹⁹ joule/1 eV) = 5.76×10²³ Joules
Next, we can determine the velocity of each He atom from the kinetic energy:
KE = 1/2*mv²
5.76×10²³ Joules = 1/2*(4)(v²)
This solves to give us: v = 5.367×10¹¹ m/s
A heavier player collides with a lighter player using greater force.
The lighter player sustains more injuries following the impact.
Explanation:
A heavier player impacts a lighter player with greater intensity, resulting in more pronounced injuries to the lighter player post-collision.
Force is defined as mass multiplied by the acceleration of an object;
Force = mass x acceleration
We observe that as mass and acceleration increase, the force exerted rises accordingly.
Clearly, the heavier player's mass surpasses that of the lighter player, leading to a greater force exerted upon collision.
Moreover, the lighter player is likely to be injured more severely after the clash. The momentum generated by the heavier player during the impact is considerably significant. Once they collide, the lighter player will certainly alter their speed and trajectory.
Learn more:
Momentum
Answer:
81°C.
Justification:
We can arrive at this conclusion using the formula:
Q = m.c.ΔT,
where Q denotes the heat lost by water (Q = - 1200 J).
m represents the mass of water (m = 20.0 g).
c indicates the specific heat of water (c = 4.186 J/g.°C).
ΔT signifies the difference between the starting temperature and the final temperature (ΔT = final T - initial T = final T - 95.0°C).
Given Q = m.c.ΔT
It follows that (- 1200 J) = (20.0 g)(4.186 J/g.°C)(final T - 95.0°C ).
(- 1200 J) = 83.72 final T - 7953.
∴ final T = (- 1200 J + 7953)/83.72 = 80.67°C ≅ 81.0°C.
Consequently, the correct answer is: 81°C.
M1V1 = M2V2
(2.50)(100.0) = (0.550)V2
V2 = 455mL
From 100.0 mL of 2.50 M KBr, you can prepare 455 mL of 0.550 M solution.
