Answer:
The salt identified is barium chloride.
Explanation:
The moles of barium sulfate produced are 
per the reaction, 1 mole of barium sulfate arises from 1 mole of 
.
Therefore, 0.0480 moles result from:
of .
The quantity of used amounts to 10.00 g
Moles of = \frac{10.00 g}{\text{Molar mass}}[/tex]
The molar mass of is 208.33 g/mol
The closest answer to our calculation is 
.
The correct identification is barium chloride, which has a molar mass of 208.2 g/mol.
Answer: 1.14
Explanation:
To find the molarity of the acid, we will utilize the equation derived from the neutralization process:
where
are the n-factor, molarity, and volume for the acid and
represent the n-factor, molarity, and volume for NaOH.
We know that:
By substituting the known values into the equation, we get:
To determine the pH of gastric juice:
The molarity amounts to = 0.072
Thus, the pH level of the gastric juice is 1.14
Problem 2
You begin with 216 micrograms of Fermium - 253. After three days, the quantity halves, resulting in 108 micrograms left.
Another three days pass. Beginning with 108 micrograms, this amount gets halved again, leaving 54 micrograms.
Finally, after another three-day span, starting from 54 micrograms, you again halve this amount to reach 27 micrograms.
#days Amount in micrograms
0 216
3 108
6 54
9 27
Problem One
Your example is Nitrogen. Begin by completing the table, then formulate some rules to help prepare for possible alternate elements in the test. This approach is quite useful.
Table
Bond Energy Kj/Mol Bond Length pico meters
N - N 167 145
N=N 418 125
N≡N 942 110
Rules
As the number of bonds INCREASES, the energy within the bond also INCREASES
As the number of bonds INCREASES, the distance of the bond DECREASES.
Answer:
The response is provided below.
Explanation:
Numerous aspects can influence the actual results of titration. These factors vary from human error to misjudging measurements, a researcher's interpretation of color changes, and improper techniques during the experimental procedure.
Thus, to mitigate these errors, researchers must engage thoroughly throughout experimentation, and employing gross readings can assist in reducing mistakes when determining the final titre value.
Answer: The net ionic equation is 
Explanation:
A double displacement reaction involves the exchange of ions. Chemicals that dissolve in water are marked with the symbol (aq), while those that do not dissolve and remain solid are shown with (s) after their formulas.
The ion-based representation of the equation is:
"Spectator ions" are the ions that do not participate in the chemical reaction, appearing on both sides of the equation in ionic form.
Ammonium and chlorate ions are present on both sides; thus, they do not factor into the net ionic equation.
Therefore, the net ionic equation is:
