A driver with a nearly empty fuel tank may say she is "running on fumes."

1 answer:

6 0

If the vehicle runs at 20.0 miles per gallon using liquid gasoline, the maximum distance it can cover is 1.62 miles. The fuel tank of the car holds 15 gallons, which translates to 56.781 liters using the conversion of 15 × 3.7854. To calculate the number of moles of gasoline, we apply the ideal gas equation: PV = nRT. Rearranging for n gives us n = PV/RT, where: P = 747 mmHg V = 56.781 liters R (the universal gas constant) = 0.0821 liter·atm/mol·K T = 25 ∘C, which converts to 298 K (273 + 25). 1 atm equals 760 mmHg. Thus, we find n = 747 × 56.781 / (0.0821 × 760 × 298) which equals 2.281 mol. Given that the molar mass of gasoline is 101 g/mol, we calculate the mass of the gasoline as n multiplied by the molar mass: 2.281 mol × 101 g/mol results in 230.38 g. The density of liquid gasoline is 0.75 g/mL. To find the volume of gasoline available, we divide the mass of the gasoline by its density, resulting in 230.38 g ÷ 0.75 g/mL = 307.17 mL, which converts to 0.3071 liters, or 0.0811 gallons when divided by 3.7854. With the car achieving 20.0 miles per gallon, the distance it will cover equals gallons available multiplied by miles per gallon, amounting to 0.0811 × 20, totaling 1.62 miles.

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To begin, this isn't really a chemistry forum, but anyway.

This represents a limiting reagent scenario.

Set it up as a Dimensional Analysis issue.

Begin with your desired outcome.

Your goal is to find the mass of acrylonitrile (C3H3N)

so you should initiate with that (I'll abbreviate Acrylonitrile as ACL for convenience)

(g) = (53 g of ACL/1mol ACL) (2 mols ACL/2 mol C3H6)/ (1mol C3H6/42 grams) (15.0 grams)

If you calculate that, you will find that 15 grams of C3H6 yields 18.9 grams of acrylonitrile produced.

Utilize the same approach for the remaining two reactants.

So, I figured it out, and for

oxygen, I calculated 11.04 grams

and for ammonia, I calculated 15.29 grams

This means that the maximum possible production is 11.04 grams, since to create any additional amount, more O2 would be necessary, but with only 10 grams available, that's the upper limit for this reaction.

The other two reactants are in excess.

Please rate as brainliest!

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The Chemistry Regents is one of the four science Regents exams. The remaining three are Earth Science, Living Environment, and Physics. Passing at least one of these four exams is a requirement for high school graduation.

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The ionic radius of a sodium ion is 2.27 angstroms (A) . What is this length in um

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$\boxed{\sf 1Å=10^{-10}m}$