Answer:
a) True
b) True
c) False
d) True
e) True
f) True
g) True
Step-by-step breakdown:
Let A denote a set. The element a is part of A if and only if a∈A.
a) The sole element of {∅} is ∅, so it follows that ∅∈{∅}.
b) The elements of {∅, {∅}} are ∅ and {∅}, thus ∅ ∈ {∅, {∅}}.
c) As {∅} solely contains ∅, it is clear {∅}≠∅ due to {∅} having one element while ∅ has no elements. Hence, {∅} ∉ {∅} since {∅} is not an element of {∅}.
d) The one element in {{∅}} is {∅}. Thus, {∅} ∈ {{∅}}.
e) The items in {∅, {∅}} include ∅ and {∅}. The only element of {∅} is ∅. Thus, every element of {∅} appears in {∅, {∅}} too, leading to {∅} ⊂ {∅, {∅}}.
f) With elements of {∅, {∅}} being ∅ and {∅}, and since the only element of {{∅}} is {∅}, we determine that {{∅}} appears in {∅, {∅}}, which means {{∅}} ⊂ {∅, {∅}}.
g) The only element of {{∅}, {∅}} equals {{∅}} which is {∅}. Each element of {{∅}} is also within {{∅}}, therefore {{∅}} ⊂ {{∅}, {∅}}={{∅}}.