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Varvara68
14 days ago
12

A communications satellite orbiting the earth has solar panels that completely absorb all sunlight incident upon them. The total

area A of the panels is 10m2.1) The intensity of the sun's radiation incident upon the earth is about I=1.4kW/m2. Suppose this is the value for the intensity of sunlight incident upon the satellite's solar panels. What is the total solar power P absorbed by the panels?Express your answer numerically in kilowatts to two significant figures.2) What is the total force F on the panels exerted by radiation pressure from the sunlight?Express the total force numerically, to two significant figures, in units of newtons.
Physics
1 answer:
Ostrovityanka [2.2K]14 days ago
3 0

Answer:

0.000047N

Explanation:

We know that

intensity (I) = P/ A

Where

P= power

A= Area

Thus, the power absorbed can be calculated as:

Power = Intensity x Area

This equals = 1.4 x 10^3 x(10)

Thus,

14000 Watts = 14 kWatt

However, the radiation pressure can be defined as

time-averaged intensity divided by the speed of light in a vacuum

So,

P = (1.4 x 1000)/c

Also,

F= P x A

Thus,

((1.4 x 1000)/(3 x10^8)) x 10

This results in

=0.000046666N

Rounded to two significant figures gives us

=0.000047 N

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