To fit between two windows, the width of a bookshelf must be no greater than Six and one half feet. Mrs. Aguilar purchases a boo

Answer:

D

Step-by-step explanation:

You should insert the provided x and y coordinates into the equations to determine which one satisfies both points.

D is valid for both:

5 = 5/4(4)

0 = 5/4(0)

Health inspector visits once a week.
Fire inspector comes every 12 days.

a) health inspector fire inspector.
day 7.                    day 12.   
day 14.                    day 24.
day 21.                    day 36.
day 28.                    day 48.
day 35.                    day 60.

b) 12 x 7 = 84.

Both will coincide on day 84.

Answer:

Possible values for X include;

15, 30, 45, 60, and so on

Step-by-step explanation:

The parameters provided are

Number of chocolates Tanmay possessed = X

Number of chocolates given to Akash = 1/3 × X

Number of chocolates given to Sharad = 1/5 × X

Consequently, since both 3 and 5 divide X,

3 × 5 = 15 is the smallest single factor of X.

Thus, the values of X based on this minimum factor are as follows;

15 × 1 = 15

15 × 2 = 30

15 × 3 = 45

15 × 4 = 60

Therefore, potential values for X form an arithmetic series: a + (n - 1) × d

Where:

a = 15

n = 1, 2, 3, 4,...

d = 15

This results in;

15, 30, 45, 60

Answer : y>0

f(x) = 9*2^x

This function is exponential in form

Substituting positive numbers for x yields positive y values

Substituting negative numbers for x also results in positive y values

Therefore, y remains positive regardless of the value of x.

The range comprises all possible y outputs of the function

Since y is always positive, the range is y > 0

Answer:

C. 5 degrees of freedom for the numerator and 114 for the denominator

Step-by-step explanation:

Analysis of variance (ANOVA) is utilized to examine the variations among group means within a sample.

The sum of squares represents the cumulative square of variation, which refers to the deviation of each individual value from the grand mean.

Assuming there are groups and each group contains individuals, the variation can be calculated using the following formulas:

This also has the property

The numerator's degrees of freedom in this case is given by where k = 6 represents the number of groups.

The denominator's degrees of freedom in this scenario is indicated by .

The total degrees of freedom would be .

Thus, the appropriate answer would be 5 degrees of freedom for the numerator and 119 degrees of freedom for the denominator.

C. 5 numerator and 114 denominator degrees of freedom