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Mila
2 months ago
10

A 1.555-g sample of baking soda decomposes with heat to produce 0.991 g Na2CO3. Refer to Example Exercise 14.l and show the calc

ulation for the theoretical yield of Na2CO3.
What is the percent yield of sodium carbonate, Na2CO3?
6. A 1473-g unknown mixture with baking soda is heated and has a mass loss of 0.325 g. Refer to Example Exercise 14.2 and show the calculation for the percentage NaHCOs in the mixture.
Chemistry
1 answer:
KiRa [2.9K]2 months ago
7 0
a) 101%, b) 59.7%.The thermal decomposition of baking soda is represented by the equation: 2NaHCO3 → Na2CO3 + H2O + CO2. The calculation of moles from 1.555g of baking soda yields approximately 0.0185 moles. Utilizing the stoichiometry of the reaction, the theoretical yield is determined, and the percent yield is found to be 101%. Similarly, an unknown mixture of baking soda decomposing shows a percentage of NaHCO3 as 59.7%.
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Anarel [2989]

The mixture’s density is 1.57 g/cm³.


Step 1: Determine the mass of the butter.


\text{Mass} = \text{1.00 cm}^{3 } \times \frac{\text{0.680 g} }{\text{1 cm}^{3 }} = \text{0.860 g}\\

Step 2: Determine the mass of the sand.


\text{Mass} = \text{1.00 cm}^{3 } \times \frac{\text{2.28 g} }{\text{1 cm}^{3 }} = \text{2.28 g}\\

Step 3: Determine the density of the mixture.

Total mass = 0.860 g + 2.28 g = 3.14 g.

Total volume = 1 cm³ + 1 cm³ = 2 cm³

\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{\text{3.14 g} }{\text{2 cm}^{3 }} = \textbf{1.57 g/cm}{^{3}\\

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2 months ago
The ideal gas law tends to become inaccurate when Group of answer choices the pressure is raised and the temperature is lowered.
VMariaS [2998]

Answer: Option (a) is the correct answer.

Explanation:

Under conditions of low pressure and high temperature, gas molecules exhibit negligible attractions or repulsions among themselves. Hence, gases behave ideally in these scenarios.

Conversely, at low temperatures, there is a reduction in the kinetic energy of gas molecules, while high pressure compels the molecules to be closer together.

Thus, attractive forces emerge between molecules in conditions of low temperature and high pressure, causing gases to be termed real gases.

Therefore, we conclude that the ideal gas law becomes less accurate when pressure increases and temperature decreases.

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2 months ago
1. Bailey wants to find out which frozen solid melts the fastest: soda, gatorade, or orange juice. She pours each of the three l
VMariaS [2998]

First scenario:

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Control: chocolate, cloth type, cloth squares

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4 0
3 months ago
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The concentration of Si in an Fe-Si alloy is 0.25 wt%. What is the concentration in kilograms of Si per cubic meter of alloy?
KiRa [2933]

Answer: The mass of Si in kilograms is, 19.55kg/m^3

Explanation:

Given that the Si concentration in an Fe-Si alloy is 0.25 weight percent, this translates to:

Mass of Si = 0.25 g = 0.00025 kg

Mass of Fe = 100 - 0.25 = 99.75 g = 0.09975 kg

Density of Si = 2.32g/cm^3=2.32\times 10^6g/m^3

Density of Fe = 7.87g/cm^3=7.87\times 10^6g/m^3

Next, we need to find the quantity of Si in kilograms per cubic meter of alloy.

Si concentration in kilograms = \frac{\text{Weight of Si in 100 g of alloy}}{\text{Volume of 100 g of alloy}}

Si concentration in kilograms = \frac{\text{Weight of Si in 100 g of alloy}}{\frac{\text{Wight of Fe}}{\text{Density of Fe}}+\frac{\text{Wight of Si}}{\text{Density of Si}}}

By substituting all the provided values into this formula, we arrive at:

Si concentration in kilograms = \frac{0.00025kg}{\frac{99.75g}{7.87\times 10^6g/m^3}+\frac{0.25g}{2.23\times 10^6g/m^3}}

Si concentration in kilograms = 19.55kg/m^3

Hence, the mass of Si in kilograms is, 19.55kg/m^3

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A chemist is looking for an element that reacts similarly to the element lithium (LI). Which would be the best choice?
lions [2927]
Option d is the correct choice, as both belong to the alkali metals category (group one).
8 0
2 months ago
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