Answer:
a) 
b) 
c) 
Explanation:
According to the problem, the distance from the building where the ball hits is 16m, and its final elevation exceeds the initial height by 8m.
With this information, we can compute the ball’s starting speed.
a) Let's first assess the horizontal trajectory.
(1)
This gives us our initial equation.
Next, we need to examine the vertical trajectory.
Utilizing 
in our first equation (1)
Now let’s solve for t.
The ball takes two seconds to reach the adjacent building, allowing us to compute its initial speed.
b) To determine the velocity magnitude just before impact, we must calculate both x and y components.
The computed velocity magnitude is:
c) The ball's angle is:
Answer:
11109.825 N
Explanation:
Provided Information:
mass = m = 1510 kg
initial acceleration (a) = 0.75g (where g = 9.81 m/s²)
Using the formula F=ma
= (1510)*(0.75*9.81)
= 11109.825 N
(A) velocity = 2.8 m/s (B) Average force = 1.9536 Newtons.
As the parachutist is descending at a steady rate
we can conclude that
Acceleration indicates the change in velocity
given the constant velocity in this scenario
Thus, in this situation, we find the acceleration to be zero
It’s understood from Newton's second law
where a is equal to 0
Here, the force due to gravity
equals the force due to buoyancy
Hence, we can deduce
therefore
as such the upward force is counteracted by the downward force.
