An experimental drug, D, is known to decompose in the blood stream. Tripling the concentration of the drug increases the decompo

Response:

FALSE

Rationale:

Sedimentary rocks are defined as rocks formed through the processes of compaction and cementation. Initially, sediments derived from various locations must accumulate. Over time, these deposited sediments undergo substantial compaction due to the weight of the layers above. This process converts loose sediments into solid rock. This is the process through which sedimentary rocks, comprised of sand-sized particles, are formed. For instance, examples include Shale, Sandstone, and Mudstone.

Thus, both compaction and cementation are crucial in the formation of sedimentary rocks.

Therefore, the statement above is False.

Although multiple values are given, our focus is on HCl.

<span>We have 215 mL (0.215 L) of 0.300 M HCl fully consumed in the reaction. It's important to recall that the number of moles is found by multiplying volume by molarity:</span>

moles = 0.215 L × 0.300 M

<span>moles = 0.0645 moles of HCl</span>

The mixture’s density is 1.57 g/cm³.

Step 1: Determine the mass of the butter.

Step 2: Determine the mass of the sand.

Step 3: Determine the density of the mixture.

Total mass = 0.860 g + 2.28 g = 3.14 g.

Total volume = 1 cm³ + 1 cm³ = 2 cm³

Answer:

2.5 g of platinum

Explanation:

A catalyst is a substance added to a reaction to enhance the reaction speed. It does not undergo any change during the reaction, meaning it remains unchanged after the reaction concludes. The role of a catalyst is to provide an alternative pathway for the reaction by reducing the activation energy required. Therefore, a catalyzed reaction occurs more rapidly and requires less energy compared to an uncatalyzed one.

Since catalysts do not get involved in reactions and retain their mass post-reaction, the amount of platinum will stay the same (2.5g). The mass can only alter if a substance participates in the chemical process. Thus, this is the response.

Response:

0.8853 mL

Clarification:

Initially, we convert 13 lb to kg, remembering that 1 lb = 0.454 kg:

• 13 lb * = 5.902 kg

Next, we determine the required mg of acetaminophen to administer, applying the recommended dosage and infant's weight:

• 15 mg/kg * 5.902 kg = 88.53 mg

Finally, we compute the necessary mL of suspension, utilizing its concentration:

• 88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mL