For each set of dilutions (bleach and mouthwash), the first tube contained a 1:11 dilution (0.5 mL of agent was added to 5.0 mL

Answer: The air in the room weighs 37.068 kg

Explanation:

Given dimensions:

Length = 10.0 ft

Width = 11.0 ft

Height = 10.0 ft

The volume of the room (rectangular prism) is calculated using:

where l = length, b = breadth, h = height.

Substituting the values,

Using the conversion:

Next, calculate the mass of the air based on density:

Conversion: 1 kg = 1000 g

Thus, the air mass in the room equals 37.068 kilograms.

B is identified as an ionic compound. Explanation: This conclusion is drawn based on the characteristics of ionic compounds, which typically form crystals similar to salt (sodium chloride), are soluble in water, exhibit high boiling and melting points, possess hardness from strong intermolecular forces, and can conduct electricity—though only when dissolved or in a molten state.

1. The luminol stock solution has a molarity of 1.431 M.

2. In 2.00 L of the diluted spray, there are 0.12 moles of luminol.

3. The volume of the stock solution from Part A that contains the same number of moles present in the diluted solution from Part B is 83.86 ml.

Additional Information

Stoichiometry in Chemistry focuses on the quantitative aspects of chemical reactions, which includes calculations related to volume, mass, and the count of ions, molecules, and elements.

Key concepts in stoichiometry include:

• 1. Relative atomic mass
• 2. Relative molecular mass

This refers to the relative atomic mass of a molecule.

• 3. Mole

A mole represents the number of particles in a substance equivalent to the number of atoms in 12 grams of carbon-12.

1 mole = 6.02 × 10²³ particles.

The quantity of moles can also be derived by dividing mass (in grams) by either the relative mass of an element or the relative mass of a molecule.

Luminol (C₈H₇N₃O₂) is utilized for detecting blood traces at crime scenes, due to its reaction with iron found in blood.

To prepare a luminol stock solution, 19.0 g of luminol is mixed into a total volume of 75.0 mL of water.

Thus, the molarity is calculated as:

• 1. Moles of Luminol

- the relative molecular mass of Luminol:

= 8.C + 7.H + 3.N + 2.16

= 8.12 + 7.1 + 3.14 + 2.16

= 177 grams/mol.

Thus, we have:

moles = grams / relative molecular mass.

moles = 0.1073.

2. Molarity (M)

M = moles / volume

M = 1.431.

• b. The concentration of luminol in the spray bottle is 6.00 × 10⁻² M. Therefore, in a 2 L solution, the number of moles is:

moles = M × volume

moles = 6 × 10⁻² × 2

moles = 0.12.

• c. The molarity of the stock solution (Part A) is 1.431 M.

The diluted solution (Part B) contains 0.12 moles of luminol.

To find the volume of the stock solution (Part A) that has the same moles as the diluted solution (Part B):

volume = moles / M

volume = 0.08386 L = 83.86 mL.

Further Learning

moles of water you can generate

the amount of each atom in the chemical's formula

the proportion of hydrogen to oxygen atoms in 2 L of water

Keywords: mole, volume, molarity, Luminol, relative molecular mass