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DaniilM
2 months ago
5

An experimental procedure says to accurately weigh approximately 1 g of substance an analytical balance. Which of the following

measurements are consistent with these instruction select all that apply a 1.0456 g B 1.0 g C 0.9811 g D1 gram 1.01 g E .99
Chemistry
2 answers:
alisha [2.9K]2 months ago
7 1

Answer:

B 1.0 g

Explanation:

Greetings,

Upon analyzing the significant figures, it's evident that 1 g has merely one significant figure. Consequently, among the provided choices, we should go with the one that closely matches this, hence the right answer is B 1.0 g since this measurement fits the required value.

Best wishes.

lorasvet [2.7K]2 months ago
0 0

The term accurately indicates that your balance meets the accuracy standards for the specified weight. Approximately implies +/- 10% of the target weight, leading to a range of 0.900 to 1.100 g for a 1 g target using a balance that ensures 0.10% accuracy at that weight. Please refer to USP definitions for further clarification.

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A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200
castortr0y [3046]

Answer:

81°C.

Justification:

We can arrive at this conclusion using the formula:

Q = m.c.ΔT,

where Q denotes the heat lost by water (Q = - 1200 J).

m represents the mass of water (m = 20.0 g).

c indicates the specific heat of water (c = 4.186 J/g.°C).

ΔT signifies the difference between the starting temperature and the final temperature (ΔT = final T - initial T = final T - 95.0°C).

Given Q = m.c.ΔT

It follows that (- 1200 J) = (20.0 g)(4.186 J/g.°C)(final T - 95.0°C ).

(- 1200 J) = 83.72 final T - 7953.

∴ final T = (- 1200 J + 7953)/83.72 = 80.67°C ≅ 81.0°C.

Consequently, the correct answer is: 81°C.

7 0
2 months ago
If the density of carbon tetrachloride is 1.59 g/ml, what is the volume in l, of 4.21 kg of carbon tetrachloride
Tems11 [2777]

Density is defined as the mass-to-volume ratio. The formula for density can be expressed as:

density = \frac{mass}{volume}    -(1)

The density for carbon tetrachloride is provided as 1.59 g/ml   (given).

The mass of carbon tetrachloride is 4.21 kg   (as given).

Since, 1 kg = 1000 g

Thus, 4.21 kg = 4210 g

Utilizing the values in formula (1):

1.59 g/mL = \frac{4210 g}{volume}

volume = \frac{4210 g}{1.59 g/mL}

volume = 2647.799 mL

Since, 1 mL = 0.001 L

Hence, 2647.799 mL = 2.65 L

The resulting volume of carbon tetrachloride is 2.65 L.


6 0
3 months ago
what is the net ionic equation with its physical states? (NH4)2CO3(aq)+Ca(ClO4)2(aq)⟶CaCO3(s)+2NH4ClO4(aq)
lions [2927]

Answer: The net ionic equation is CO_3^{2-}(aq)+Ca^{2+}(aq)\rightarrow CaCO_3(s)

Explanation:

A double displacement reaction involves the exchange of ions. Chemicals that dissolve in water are marked with the symbol (aq), while those that do not dissolve and remain solid are shown with (s) after their formulas.

(NH_4)_2CO_3(aq)+Ca(ClO_4)_2(aq)\rightarrow CaCO_3(s)+2NH_4ClO_4(aq)

The ion-based representation of the equation is:

2NH_4^+(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2ClO_4^{-}(aq)\rightarrow CaCO_3(s)+2NH_4^{+}(aq)+2ClO_4^-(aq)

"Spectator ions" are the ions that do not participate in the chemical reaction, appearing on both sides of the equation in ionic form.

Ammonium and chlorate ions are present on both sides; thus, they do not factor into the net ionic equation.

Therefore, the net ionic equation is:

CO_3^{2-}(aq)+Ca^{2+}(aq)\rightarrow CaCO_3(s)

6 0
2 months ago
Put the following elements into five pairs of elements that have similar chemical reactivity: F, Sr, P, Ca, O, Br, Rb, Sb, Li, S
Anarel [2989]

Explanation:

Elements provided:

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Elements sharing similar reactivity belong to the same group in the periodic table, indicating that those in the same column exhibit comparable reactivity. Here are the identified groupings:

  Li and Rb are alkali metals in group 1

  Ca and Sr are alkaline earth metals in group 2

  F and Br are halogens in group 7

  O and S belong to group 6

 P and Sb are classified in group 5 of the periodic table

Thus, these classifications illustrate elements with the same chemical characteristics.

7 0
3 months ago
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KiRa [2933]
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5 0
2 months ago
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