The mass of the Sun is 2multiply1030 kg, and the mass of the Earth is 6multiply1024 kg. The distance from the Sun to the Earth i
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Answer:
5.7 m
Explanation:
AD = length of the ladder = L = 8 m
AB = the position of the ladder's center of mass = (0.5) L = (0.5) 8 = 4 m
AC = distance of the climber from the bottom of the ladder = x
W = weight of the ladder = 240 N
= weight of the climber = 710 N
F = force exerted by the wall on the ladder
N = normal force acting on the ladder from the ground =?
By applying force equilibrium in the vertical direction
N = + W
N = 710 + 240
N = 950 N
μ = Coefficient of static friction = 0.55
f = static friction force on the ladder
Static friction force can be expressed as
f = μ N
f = (0.55) (950)
f = 522.5 N
The equation for force along the horizontal axis reads
F = f
F = 522.5 N
using torque equilibrium around point A
F Sin50 (AD) = W Cos50 (AB) + ( Cos50 (AC))
(522.5) Sin50 (8) = (240) Cos50 (4) + (710) Cos50 (x)
x = 5.7 m
Response:
The speed at which the distance from the helicopter to you is changing (in ft/s) after 5 seconds is ft/ sec
Clarification:
Provided:
h(t) = 25 ft/sec
x(t) = 10 ft/ sec
h(5) = 25 ft/sec. 5 = 125 ft
x(5) = 10 ft/sec. 5 = 50 ft
At this point, we can determine the distance between the individual and the helicopter utilizing the Pythagorean theorem
Now, let's calculate the derivative of distance in relation to time
By plugging in the values for h(t) and x(t) and simplifying, we arrive at,
=
=
ft / sec