If the patient has to be administered a dosage of 2 tablets every 8 hours for 7 days, what is the number of tablets required for
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A pressure of 137.14 MPa exists 10,000 m beneath the ocean surface.
At this same depth, the density measures 2039 kg/m3.
Explanation:
P0 and ρ0 symbolize the pressure and density at sea level (indicative of atmospheric conditions). With an increase in ocean depth, both pressure and density likewise rise.
The relationship between pressure and density can be expressed as:
By rearranging
This equation allows for computation of P at 10,000 m beneath the ocean's surface:
The density found at a depth of 10,000 m in the ocean is
The problem provides a conversion factor---> 1 mm3= 7.0 x 10^6 RBC. Therefore, to determine the quantity of red blood cells in your sample, we must first convert Liters to cm3 using the conversion factor--> 1 mL= 1 cm3
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I have shared how to resolve this issue.
As the ball descends down the hill, its potential energy diminishes while its kinetic energy rises.
The ball's potential energy will decrease as it moves down the slope, and its kinetic energy will experience an increase.
Kinetic energy refers to the energy possessed by an object in motion.
K. E = m v²
where m is the mass of the ball
and v represents the ball's velocity.
Potential energy is the energy associated with an object's position as it traverses down a slope, expressed as:P.E = mgh
with m as the mass of the ball,
g as gravitational acceleration, and h as the height.It is clear that as the object descends, its height decreases, while its velocity increases.
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Respuesta:
0.16 M
Explicación:
Teniendo en cuenta:
O sea,
Dado que:
Para :
Molaridad = 0.200 M
Volumen = 20.0 mL
Convierte mL a L:
1 mL = 10⁻³ L
Entonces, volumen = 20.0×10⁻³ L
Los moles de son:
Moles de = 0.004 moles
Para :
Molaridad = 0.400 M
Volumen = 30.0 mL
Convertimos mL a L:
1 mL = 10⁻³ L
Volumen = 30.0×10⁻³ L
Entonces, los moles de son:
Moles de = 0.012 moles
Según la reacción:
1 mol de reacciona con 1 mol de
Por lo tanto,
0.012 mol de reacciona con 0.012 mol de
Moles disponibles de = 0.004 mol
El reactivo limitante es el que está en menor cantidad, entonces es el limitante (0.004 < 0.012).
La formación del producto depende del reactivo limitante, así que,
1 mol de reacciona con 1 mol de
y produce 1 mol de
0.004 mol de reacciona con 0.004 mol de
y genera 0.004 mol de
Los moles restantes de son: 0.012 - 0.004 = 0.008 mol
El volumen total es 20 + 30 mL = 50 mL = 0.050 L
Por lo que la concentración del ion bario, , después de la reacción es: