Write a balanced half-reaction for the reduction of aqueous nitrous acid hno2 to gaseous nitric oxide no in basic aqueous soluti

Cu(NO3)2 --> MM187.5558 NiNO3 *COEF2* --> 120.6983

1) To express 0.89% m/v, it equals 0.89 grams of NaCl per 100 ml of solution.

This corresponds to 8.9 grams of NaCl in 1000 ml of solution, or 8.9 grams in 1 liter.

2) Molarity is represented as M = moles of solute / liters of solution.

Thus, we need to determine the moles in 8.9 grams of NaCl.

3) The molar mass of NaCl is calculated as 23.0 g/mol + 35.5 g/mol = 58.5 g/mol.

4) Therefore, the number of moles of NaCl calculates as mass / molar mass = 8.9 g / 58.5 g/mol = 0.152 moles.

5) Consequently, M = 0.152 moles of NaCl / 1 liter of solution = 0.152 M.

Answer: 0.152 M

Explanation:

Filtration serves as a method of separation where solid particles that are suspended in a liquid are isolated by passing the mixture through filter paper's pores. This process ensures that the solid particles accumulate on the filter paper and the liquid flows out through the filter paper's pores.

The ordered sequence of the steps provided is:

1. Measure and fold the filter paper.
2. Insert the filter paper into the funnel, then position the funnel above the Erlenmeyer flask.
3. Let the solid/liquid mixture pass through the filter.
4. Rinse the filter paper that holds the mixture with water.
5. Measure the weight of the dry filter paper along with the copper.

The balloon's volume is 128 ml when the gas temperature rises to 320.0 K. Explanation: Given the following: T1 (initial temperature) = 300K, V1 (initial volume) = 120ml, T2 (final temperature) = 320 K, V2 (final volume) =?. Pressure is kept constant during this process. From the equation: Given that the pressure stays constant, we have: V2 = Putting the values into this formula yields: V2 = 128 ml, which indicates the volume of the gas when the temperature increases from 300 K to 320 K.