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vaieri
2 months ago
11

Examine the sets of bonds given in the choices. which one arranges the bonds in order of increasing (shortest to longest) bond l

ength? examine the sets of bonds given in the choices. which one arranges the bonds in order of increasing (shortest to longest) bond length? c—cl, c—f, c—br, c—i c—i, c—br, c—cl, c—f c—f, c—cl, c—i, c—br c—f, c—cl, c—br, c—i
Chemistry
1 answer:
Tems11 [2.7K]2 months ago
8 0
The stronger the attraction between elements, the shorter the bond length becomes; conversely, a weaker attraction results in a longer bond length. This attraction arises from differences in their electronegativities, which is the capacity of an element to draw electrons toward itself. According to periodic trends, electronegativity rises as you move left to right and bottom to top on the periodic table. Therefore, the order from the most electronegative to the least is: Cl > Br > I. As a result, the sequence by bond length from shortest to longest is: C-Cl > C-Br > C-I.
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Several amino acids are intermediates of the urea cycle, having side ammonia groups that join with free carbon dioxide (CO2) and
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Excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide to produce aqueous sodium nitrate and copper(II) sulfide as
Tems11 [2777]

The question lacks completeness; the full question is:

Determine the theoretical yield:

When excess aqueous copper(II) nitrate reacts with aqueous sodium sulfide, sodium nitrate and copper(II) sulfide precipitate. For this reaction, 469 grams of copper(II) nitrate was combined with 156 grams of sodium sulfide yielding 272 grams of sodium nitrate.

Answer:

The theoretical yield of sodium nitrate is 340 grams.

Explanation:

Cu(NO_3)_2(aq)+Na_2S(aq)\rightarrow 2NaNO_3(aq)+CuS(s)

Calculating moles of copper(II) nitrate = \frac{469 g}{187.5 g/mol}=2.5013 mol

Moles of sodium sulfide = \frac{156 g}{78 g/mol}=2 mol

Based on the reaction, 1 mole of copper(II) nitrate reacts with 1 mole of sodium sulfide.

Thus, 2 moles of sodium sulfide will react with:

\frac{1}{1}\times 2mol= 2 mol of copper(II) nitrate

Since sodium sulfide is in limiting quantities, the amount of sodium nitrate produced will depend on the moles of sodium sulfide available.

According to the reaction, 1 mole of sodium sulfide generates 2 moles of sodium nitrate; thus, 2 moles of sodium sulfide will yield:

\frac{2}{1}\times 2mol=4 mol sodium nitrate

The total mass of 4 moles of sodium nitrate is:

85 g/mol × 4 mol = 340 g

The theoretical yield of sodium nitrate amounts to 340 g.

The theoretical yield of sodium nitrate is 340 grams.

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1 month ago
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