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Serhud
1 day ago
14

How can you prepare 100.0 ml of 0.400 m CaCl2 from a stock solution of 2.00 m CaCl2.

Chemistry
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What is the mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water
Tems11 [2777]

Response:

The mass percentage of a solution comprising 7.6 grams of sucrose and 83.4 grams of water equals 8.351 %.

Details:

Provided data:

Sucrose mass = 7.6 grams

Water mass = 83.4 grams

In this scenario, sucrose acts as the solute, while water is the solvent.

The calculation for mass percent of a solution is done using the following formula:

Mass percent = (Mass of Solute/Mass of Solution)(100)

As sucrose is the solute, the mass equals 7.6 grams.

The total mass of the solution, which includes both sucrose and water, comes out to:

Total mass = 7.6 grams + 83.4 grams = 91 grams

Therefore, applying the values gives mass percent = (7.6/91)(100) = 8.351 %.

7 0
3 months ago
Why can metallic elements bend, while solid but non-metallic break or crumble?
Anarel [2989]
Metallic elements demonstrate ductility, enabling them to bend. This property means that a solid material can elongate when tensile stress is applied. Ductile materials can potentially be drawn into wires. Additionally, these materials often exhibit malleability. 
5 0
2 months ago
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Pyridine rings can also under electrophilic aromatic substitution. given 2-methoxypyridine below, draw the expected major produc
alisha [2963]
Co2 is indeed the correct answer, my friend.
8 0
1 month ago
N2 and H2 are mixed in 14:3 mass ratio. After certain time ammonia was found to be 40% by mol. The mole fraction of N2 at that t
lorasvet [2795]

Answer: The mole fraction of nitrogen is calculated to be 0.4615.


Explanation: In the mixture of nitrogen (N_{2}) and hydrogen (H_{2}), the mole ratio established is 1: 1.5.


At this juncture, we identify that (H_{2}) serves as the limiting reagent.


When 0.4 moles of (NH_{3}) are produced, it will require 0.4 moles of (N_{2}) along with 3.4 moles of (H_{2}).


The total amount of remaining (N_{2}) ends up being 0.6, while the amount of (H_{2}) left in the mixture is 0.3 moles.


The mole fraction of (N_{2}) is computed as 0.6 divided by the sum of 0.6, 0.4, and 0.3, resulting in 0.4615.

8 0
3 months ago
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