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Ksenya-84
16 days ago
10

A loop of wire with cross-sectional area 1 m2 is inserted into a uniform magnetic field with initial strength 1 T. The field is

parallel to the axis of the loop. The field begins to grow with time at a rate of 2 Teslas per hour. What is the magnitude of the induced EMF in the loop of wire
Physics
1 answer:
serg [3.5K]16 days ago
8 0

Answer:

La magnitud del EMF es 0.00055  volts

Explanation:

El EMF inducido es proporcional al cambio en el flujo magnético según la ley de Faraday:

emf\,=-\,N\, \frac{d\Phi}{dt}

Como en nuestro caso hay solo un lazo de alambre, entonces N=1 y obtenemos:

emf\,=-\,N\, \frac{d\Phi}{dt}

Necesitamos expresar el flujo magnético dada la geometría del problema;

\Phi=B\,\,Adonde A es el área de la bobina que permanece constante con el tiempo, y B es el campo magnético que cambia con el tiempo. Por lo tanto, la ecuación para el EMF se convierte en:

emf\,=-\,N\, \frac{d\Phi}{dt} = \frac{d\Phi}{dt} =-\frac{d\,(B\,A)}{dt} =-\,A\,\frac{d\,(B)}{dt}=- 1\,m^2(2\,\,T/h})= -2\,\,m^2\,T/(3600\,\,s)= -0.00055\,Volts

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