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balandron
7 days ago
13

An arthroscope can be inserted into a knee joint through a very tiny incision to help a doctor examine the knee. A light is tran

smitted through the scope to illuminate the joint.
What type of light technology is being described?
Physics
2 answers:
Yuliya22 [2.4K]7 days ago
8 0

Response:

Total Internal Reflection

Clarification:

An arthroscope is an optical fiber used by doctors to observe the knee. Light travels through this device due to the process of total internal reflection. When light hits the boundary of a denser medium at a specific angle greater than the critical angle, it is completely reflected back. This principle allows light to pass through thin optical fibers, accommodating various applications.

inna [2.2K]7 days ago
4 0

Example Response: The technology referenced is fiber optics. Their small size and flexibility allow doctors to visualize areas that would otherwise require surgical intervention to examine.

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The intensity level of a "Super-Silent" power lawn mower at a distance of 1.0 m is 100 dB. You wake up one morning to find that
Maru [2355]

Answer:

The correct option is 80 dB.

Explanation:

The transformation of sound intensity level into sound intensity utilizes the formula

[D] = 10 log (I/I₀)

Where I₀ = 10⁻¹² W/m²

[D] results in 100 dB

100 = 10 log (I/I₀)

Log (I/I₀) converts to 10

(I/I₀) = 10¹⁰

I is determined as I₀ × 10¹⁰ = 10⁻¹² × 10¹⁰ = 10⁻² W/m²

Sound intensity inversely relates to the square of the distance from the source.

I ∝ (1/d²)

I can be expressed as k/d²

When d = 1 m, the intensity is 10⁻² W/m²

Thus, 0.01 = k/1

Providing that k = 0.01 W

For d = 20 m, we can calculate I

I = 0.01/20² = 2.5 × 10⁻⁵ W/m²

With four neighbors mowing their lawns concurrently,

I = 4 × 2.5 × 10⁻⁵ = 10⁻⁴ W/m⁻²

The sound intensity level in decibels is represented as

[D] = 10 log (I/I₀)

[D] = 10 log (10⁻⁴/10⁻¹²)

[D] = 10 log (10⁸)

[D] = 10 × 8 = 80dB

4 0
18 days ago
A 1000-kg car is moving along a straight road down a 30∘30∘ slope at a constant speed of 20.0m/s20.0m/s. What is the net force a
Softa [2029]

The overall force acting on the vehicle is zero

Explanation:

Let's evaluate the situation separately for the vertical direction and the horizontal direction along the slope.

Considering the direction perpendicular to the slope, two forces are in effect:

  • The weight component acting perpendicular to the slope, mgcos \theta, directed into the slope
  • The normal force N, directed outward from the slope

Equilibrium exists here, indicating the net force in this direction is zero.

Now let’s examine the parallel direction to the slope. We have two forces present:

  • The weight component aligned with the slope, mgsin \theta, directed down the slope
  • The frictional force F_f, acting up the slope

The car moves at a constant speed in this direction, indicating that its acceleration is zero.

a=0

Thus, according to Newton's second law,

F=ma

implying the net force is zero:

F=0

Learn more about slopes and friction:

5 0
21 day ago
By constructing basic electric circuits, you will be able to measure current flow. With Ohm’s law in mind, what broad question a
Ostrovityanka [2204]

Broad questions addressed by conducting this experiment involve the effects of electric current.

Additional details

Electric current measures the quantity of electric charge passing per unit time.

It results from electrons moving due to a voltage difference (high potential to low potential) between two points.

These electrons flow through wires acting as conductors.

Ohm's Law states that:

The potential difference across a conductor is proportional to the current flowing through it, assuming resistance remains the same.

\displaystyle I=\frac{V}{R}\\\\V=I\times R

A basic electrical circuit consists of a voltage source (battery) and a lamp.

Ammeters used to measure current must be connected in series with the load.

By adjusting the voltage while resistance is constant, varying current values are observed; increasing voltage produces higher current.

Learn more

Electron flow inside devices

brainly.com/question/4438943

Keywords: basic electric circuits, Ohm's law, experiment

5 0
1 month ago
Read 2 more answers
Two charges of 15 pC and −40 pC are inside a cube with sides that are of 0.40-m length. Determine the net electric flux through
Keith_Richards [2256]

To address this issue, we will utilize the principles related to Gauss' law, which states that the electric flux across a surface corresponds to the object's charge divided by the permittivity of vacuum. In mathematical terms, this can be expressed as

\phi = \frac{Q_{net}}{\epsilon_0}

It's crucial to remember that the net charge equals the difference between the two specified charges, so upon substitution,

\phi = \frac{(15-40)*10^{-12}C}{8.85*10^{-12}C^2/Nm^2}

\phi = 2.82WB

The negative sign indicates that the flux is directed into the surface

4 0
25 days ago
Two infinite parallel surfaces carry uniform charge densities of 0.20 nC/m2 and -0.60 nC/m2. What is the magnitude of the electr
Yuliya22 [2420]

Answer:

The electric field strength, E = 45.19 N/C

Explanation:

It is indicated that,

Surface charge density on the first surface, \sigma_1=0.2\ nC/m^2=0.2\times 10^{-9}\ C/m^2

Surface charge density on the second surface, \sigma=-0.6\ nC/m^2=-0.6\times 10^{-9}\ C/m^2

The electric field at a location between the two surfaces can be calculated as:

E=\dfrac{\sigma}{2\epsilon_o}

E=\dfrac{\sigma1-\sigma_2}{2\epsilon_o}

E=\dfrac{0.2\times 10^{-9}-(-0.6\times 10^{-9})}{2\times 8.85\times 10^{-12}}

Consequently, E = 45.19 N/C

Therefore, the electric field's magnitude at a point between both surfaces is 45.19 N/C.

6 0
17 days ago
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