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spayn
10 days ago
9

How far will a rubber ball fall in 10 seconds?

Physics
1 answer:
serg [2.5K]10 days ago
4 0

If the object remains stationary at the onset of 10 seconds, it will descend 490 meters straight downward over 10 seconds.

(Note: This holds true for all items on Earth... rubber balls, feathers, grains of sand, school buses, battleships... everything. As long as air resistance is not an issue. Any object dropped from rest falls 490 meters in the initial 10 seconds.)

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1. Use Coulomb’s Law (equation below) to calculate the approximate force felt by an electron at point A in the schematic below.
Keith_Richards [2263]

Answer:

Explanation:

The data indicates that point A is located midway between two charges.

To calculate the electric field at point A, we begin with the field produced by charge -Q ( 6e⁻ ) at A:

= 9 x 10⁹ x 6 x 1.6 x 10⁻¹⁹ / (2.5)² x 10⁻⁴

= 13.82 x 10⁻⁶ N/C

This field points towards Q⁻.

A similar field will arise from the charge Q⁺, but it will direct away from Q⁺ toward Q⁻.

To find the resultant field, we add these contributions:

= 2 x 13.82 x 10⁻⁶

= 27.64 x 10⁻⁶ N/C

For the force acting on an electron placed at A:

= charge x field

= 1.6 x 10⁻¹⁹ x 27.64 x 10⁻⁶

= 44.22 x 10⁻²⁵ N

8 0
17 days ago
A person on a cruise ship is doing laps on the promenade deck. on one portion of the track the person is moving north with a spe
kicyunya [2264]
The resulting motion can be determined using the Pythagorean theorem, as the two components (north and east) are at right angles. To find the direction, trigonometry is applied, yielding Ф=arctan(3.8/12)=17.57° north of east.
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5 days ago
Read 2 more answers
A tennis ball bounces on the floor three times. If each time it loses 22.0% of its energy due to heating, how high does it rise
Ostrovityanka [2208]

Answer:

H = 109.14 cm

Explanation:

Given,                                                            

Assume that the total energy equals 1 unit.                                

Energy remaining after the first collision = 0.78 x 1 unit

Balance after the first impact = 0.78 units

Remaining energy after the second impact = 0.78 ^2 units

Balance after the second impact = 0.6084 units

Remaining energy after the third impact = 0.78 ^3 units

Balance after the third impact = 0.475 units

The height reached after the third collision is equivalent to the remaining energy.

Let H denote the height achieved after three bounces.

0.475 (m g h) = m g H                  

H = 0.475 x h                                    

H = 0.475 x 2.3 m                          

H = 1.0914 m                      

H = 109.14 cm                      

6 0
16 days ago
While dangling a hairdryer by its cord, you observe that the cord is vertical when the hairdryer isoff and, once it is turned on
Yuliya22 [2438]

Answer:

The air exiting from the hairdryer is moving at a speed of 10 m/s.

Explanation:

The thrust generated by the hairdryer enables it to maintain an elevation angled at 5° from vertical; thus, we derive from the force diagram

(1).\: tan (5^o) = \dfrac{F_t}{Mg}

by substituting M =0.420kg, g = 9.8m/s^2 into the equation and resolving for F_t we find:

F_t = Mg\:tan(5^o)

F_t = (0.420kg)(9.8m/s^2)\:tan(5^o)

\boxed{F_t = 0.3601N.}

This thrust is linked to the speed of air ejection v through the equation

(2).\: F_t = v\dfrac{dM}{dt}

where dM/dt signifies the rate of air ejection, which is known to be

0.06m^3/2s  = 0.03m^3/s

and since 1m^3 = 1.2kg,

0.03m^3/s \rightarrow 0.036kg/s

\dfrac{dM}{dt}  = 0.036kg/s,

by inserting these values into equation (2), we obtain the value of F_t as:

0.3601N = 0.036v

resulting in

v= \dfrac{0.3601}{0.036}

\boxed{v =10m/s.}

which indicates the air velocity discharged from the hairdryer.

6 0
1 month ago
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