Answer: The number of sulfur dioxide molecules present is 1.27·10²³.
Calculating: m(SO₂) equals 13.5 g.
Using the formula n(SO₂) = m(SO₂) ÷ M(SO₂).
This gives n(SO₂) = 13.5 g ÷ 64 g/mol.
Resulting in n(SO₂) = 0.21 mol.
Subsequently, N(SO₂) = n(SO₂) ·Na.
Therefore, N(SO₂) = 0.21 mol · 6.022·10²³ 1/mol.
Ultimately, N(SO₂) equals 1.27·10²³.
Where n represents amount of substance.
M refers to molar mass.
Na is Avogadro's number.
Answer:
The yield percentage of H_2CO_3 is 24.44%
Explanation:
The scenario that would lead to an endothermic ΔHsolution is when |ΔHsolute| > |ΔHhydration|. Explanation: A solution is characterized as a homogeneous mixture of two or more substances that can exist in gas, liquid, or solid forms. The enthalpy of solution may either be positive (indicating an endothermic reaction) or negative (indicating an exothermic reaction). Enthalpy represents the heat released or absorbed during the dissolution process at constant pressure. The initial step of this process involves separating the solute, which breaks all the intermolecular forces binding the solute together. This separation is an endothermic process, requiring energy to disrupt these interactions. Therefore, ΔH1 is positive. Consequently, for this situation to result in an endothermic reaction, the enthalpy of the solute must exceed the enthalpy of hydration.
Answer:
0.20M of nitric acid
0.00250M of KSCN
Explanation:
In the case of nitric acid, the solution's dilution changes from 10.00mL to 100.00mL, resulting in a 1/10 dilution. Given the original concentration of nitric acid is 2.0M, the updated concentration becomes: 2.0M×(1/10)=0.20M of nitric acid
Similarly, the dilution of KSCN extends from 50.00mL to 100.00mL, equal to a 1/2 dilution. Consequently, the new concentration of KSCN turns out to be:
0.00500M × (1/2) = 0.00250M of KSCN
I hope it aids you!
