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asambeis
1 month ago
8

Choose the situation below that would result in an endothermic ΔHsolution.

Chemistry
1 answer:
alisha [2.9K]1 month ago
4 0
The scenario that would lead to an endothermic ΔHsolution is when |ΔHsolute| > |ΔHhydration|. Explanation: A solution is characterized as a homogeneous mixture of two or more substances that can exist in gas, liquid, or solid forms. The enthalpy of solution may either be positive (indicating an endothermic reaction) or negative (indicating an exothermic reaction). Enthalpy represents the heat released or absorbed during the dissolution process at constant pressure. The initial step of this process involves separating the solute, which breaks all the intermolecular forces binding the solute together. This separation is an endothermic process, requiring energy to disrupt these interactions. Therefore, ΔH1 is positive. Consequently, for this situation to result in an endothermic reaction, the enthalpy of the solute must exceed the enthalpy of hydration.
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KiRa [2933]

Answer:

Is it true that you shouldn't wash your hair, drink cold water, eat ice cream, or exercise during your period? Please explain your answer.

No, this is not accurate; doing any of these activities is perfectly fine. None of them affects us because they are not connected to our bodily systems. Also, I apologize for any language errors as I utilized Google Translate.

I hope this is helpful :)

7 0
3 months ago
A 0.2500 g sample of a compound known to contain carbon, hydrogen and oxygen undergoes complete combustion to produce 0.3664 gra
lorasvet [2795]

Answer:

C₂H₅O₂

Explanation:

From the information provided in the question, we have the following details:

Mass of compound = 0.25 g

Mass of CO₂ = 0.3664 g

Mass of H₂O = 0.15 g

Empirical formula =?

Now, let’s calculate the masses of carbon, hydrogen, and oxygen within the compound as follows:

For Carbon (C):

Mass of CO₂ = 0.3664 g

Molar mass of CO₂ = 12 + (2×16) = 44 g/mol

Mass of C = 12/44 × 0.3664

Mass of C = 0.1

For Hydrogen (H):

Mass of H₂O = 0.15 g

Molar mass of H₂O = (2×1) + 16 = 18 g/mol

Mass of H = 2/18 × 0.15

Mass of H = 0.02 g

For Oxygen (O):

Mass of C = 0.1 g

Mass of H = 0.02 g

Mass of compound = 0.25 g

Mass of O =?

Mass of O = (Mass of compound) – (Mass of C + Mass of H)

Mass of O = 0.25 – (0.1 + 0.02)

Mass of O = 0.25 –0.12

Mass of O = 0.13 g

In conclusion, we will now find the empirical formula for the compound:

C = 0.1

H = 0.02

O = 0.13

Next, we divide by their respective molar mass:

C = 0.1 / 12 = 0.0083

H = 0.02 / 1 = 0.02

O = 0.13 / 16 = 0.0081

Then we divide by the smallest value:

C = 0.0083 / 0.0081 = 1

H = 0.02 / 0.0081 = 2.47

O = 0.008 / 0.008 = 1

Finally, we multiply by 2 to present in whole numbers:

C = 1 × 2 = 2

H = 2.47 × 2 = 5

O = 1 × 2 = 2

Therefore, the empirical formula for the compound is C₂H₅O₂

5 0
2 months ago
Would an alkali metal make a good replacement for tin in a tin can? Explain.
Tems11 [2777]

Answer:

No

Explanation:

When heated, tin could react with alkali metals, releasing hydrogen gas.

6 0
1 month ago
mixture or pure substance: 1.blood 2.dyes 3.self-raising flour 4.muesli 5.copper wire 6.distilled water 7.table salt 8.milk 9.br
alisha [2963]

Answer: Mixture: Blood, Self raising flour,muesli,dyes, milk, tea, air, bronze

Pure substance: Copper wire, distilled water, table salt, oxygen.

Explanation:

A mixture is a substance composed of two or more compounds which are chemically independent and keep their individual chemical properties.

Examples: Blood, Self raising flour,muesli,dyes, milk, tea, air, bronze

A pure substance is defined as something with a uniform and constant composition and is called a pure substance.

Examples: Copper wire, distilled water, table salt, oxygen.

5 0
2 months ago
A Gas OCCUPIES 525ML AT A PRESSURE OF 85.0 kPa WHAT WOULD THE VOLUME OF THE GAS BE AT THE PRESSURE OF 65.0 kPa
castortr0y [3046]

Boyle's law pertaining to ideal gases states that the volume of a gas relates inversely to its pressure when temperature is constant. According to this principle, the relationship between pressure and volume can be expressed as:

PV=Constant

This implies:

P_{1}V_{1}=P_{2}V_{2}

Utilizing this equation enables us to determine the volume of gas given a specific pressure:

P₁=Initial pressure

V₁=Initial volume

P₂=Final pressure

V₂= Final volume

In this case, the initial pressure P₁ is noted as 85.0 kPa.

The initial volume V₁ is provided as 525 mL.

The final pressure P₂ is recorded as 65.0 kPa.

P_{1}V_{1}=P_{2}V_{2}

Thus,

V_{2}=85×525÷65

=686 mL

Consequently, the gas volume will amount to 686 mL.

8 0
2 months ago
Read 2 more answers
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