Answer:
In blood: Dispersed phase: blood cells; Dispersed medium: liquid plasma
In fruit jelly: Dispersed phase: fruit juice; Dispersed medium: pectin
Explanation:
The dispersed phase refers to the phase where colloidal particles are dispersed within another phase, known as the dispersion medium.
In blood, the tiny cells act as colloidal particles, forming the dispersed phase within the liquid medium identified as plasma.
Conversely, in fruit jelly, the fruit juice constitutes the dispersed phase while the solid pectin serves as the dispersed medium.
Answer: Reaction 2 is a spontaneous one.
Explanation:
According to our understanding:
= +ve, meaning the reaction is non-spontaneous
= -ve, indicating the reaction is spontaneous
= 0, stating that the reaction is at equilibrium
For a reaction to be classified as spontaneous, the Gibbs free energy must yield a negative value.
Reaction 1:
Glucose + Pi ⟶ glucose-6-phosphate + H₂O, ΔG = +13.8 kJ/mol
Reaction 2:
ATP + H₂O ⟶ ADP + Pi, ΔG = -30.5 kJ/mol
From this, we can conclude that ΔG being negative indicates that reaction 2 is indeed spontaneous.
Answer:Sugar-water is a mixture
Explanation:
If it consists of pure sugar, it's classified as neither; however, when mixed with water, it forms a homogeneous mixture.
Density is calculated as mass divided by volume.
Step one:
Convert m³ to ml.
1 m³ = 1,000,000 ml
0.250 m³ x 1,000,000 = 250,000 ml
Step two: Convert mg to g.
1 mg = 0.001 g, hence 4.25 x 10^8 mg equals 0.459 g.
Consequently, the density comes out to be 0.459 g/250,000 = 1.836 x 10^-6 g/ml.
<span>To determine the specific heat of a solid sample, I’d begin by measuring the mass of the solid. Then, I would prepare a sufficient quantity of water at room temperature to fully submerge the solid. This water would go in an insulated container. I'd then heat the solid to a known temperature. Next, I’d record both the temperature of the solid and the water. After that, I'd submerge the heated sample in the water, allowing them to reach thermal equilibrium. I would then note this final equilibrium temperature.
The temperature difference between the heated sample and the equilibrium state indicates the change in temperature of the solid. Given the known mass, initial temperature of the water, and the equilibrium temperature, I can calculate the energy transferred from the solid to the water.
With the mass of the sample, the change in temperature of the solid, and the transferred energy, I have enough information to find the specific heat of the solid sample</span>
