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Marianna
1 month ago
6

There are two kinds of elements that didn't appear on the periodic table until after 1892. What kinds are they and why do you th

ink it took so long to discover them?
Chemistry
2 answers:
Tems11 [2.7K]1 month ago
6 0

Answer:

The two elements in question are Argon and Helium.

Both belong to the noble gases and are inert in nature

Explanation:

The two types of elements are argon and helium. They were discovered in 1892 by Scottish chemist Williams Ramsay.

Categorized as noble gases or inert gases, these elements are known for their reluctance to react with others.

At the time, element discovery heavily relied on their reactivity with other elements; therefore, it took a considerable time for argon and helium to be identified due to their nonreactivecharacteristics. Combined with the fact that they are odorless, tasteless, and colorless, making them more challenging to discover.

lorasvet [2.7K]1 month ago
5 0

Your Question: There are two kinds of elements that didn't appear on the periodic table until after 1892. What kinds are they and why do you think it took so long to discover them?

The Answer: The insights of Moseley led chemists to further refine the periodic table and uncover additional gaps, indicating that several new elements, specifically with atomic numbers 43, 61, 72, and 75, remained undiscovered. These elements were later identified as technetium, promethium, hafnium, and rhenium, respectively.

Explanation: Physicist Henry Moseley used x-rays to determine the atomic number of elements, which facilitated a more accurate organization of the periodic table. His life and the discovery of the correlation between atomic number and x-ray frequency, known as Moseley's Law, are significant to note.

Remember to consult study guides, lessons, and notes; hard work is essential for success. Good Luck!

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Which best describes the relationships between subatomic particles in any neutral atom? * 1 point the number of electrons equals
Tems11 [2777]

The atomic number corresponds to the number of protons

Protons are denoted as P and Electrons as E P = E

The atomic mass equals the sum of Neutrons and Protons

Atomic number = atomic mass = neutrons

P = E

Atomic mass - atomic number = Neutrons

Example:

Calcium consists of 20 Protons 20P = 20E

Atomic mass - atomic number = neutron count:)

4 0
25 days ago
An experimental drug, D, is known to decompose in the blood stream. Tripling the concentration of the drug increases the decompo
lions [2927]

Answer:

The rate law for the decomposition reaction is:

R=k[D]^2

The unit for the rate constant will be M^{-1}s^{-1}

Explanation:

D\rightarrow Product

The rate law can be expressed as:

R=k[D]^x..[1]

When the drug concentration is tripled, the decomposition rate rises by a factor of nine.

[D]'=3[D]

R'=9\times R

R'=k[D]'^x...[2]

[1] ÷ [2]

\frac{R}{R'}=\frac{k[D]^x}{k[D']^x}

\frac{R}{9R}=\frac{k[D]^x}{k[3D]^x}

9=3^x

Solving for x results in:

x = 2.

This indicates a second-order reaction.

The decomposition reaction's rate law is:

R=k[D]^2

The unit for the rate constant will be:

k=\frac{R}{[D]^2}=\frac{M/s}{(M)^2}=M^{-1}s^{-1}

The unit for the rate constant will be M^{-1}s^{-1}.

5 0
1 month ago
Athletic trainers use instant ice packs that can be cooled quickly on demand. Squeezing the pack breaks an inner container, allo
KiRa [2933]

Answer:

Heat flow is best characterized as the transfer of heat between a system and its surroundings.

Explanation:

Heat is energy that moves spontaneously from a hotter object to a cooler one due to temperature differences among substances. In this scenario, heat can be said to flow from the surroundings, perhaps a hurt athlete's knee, to the ice packs.

7 0
14 days ago
A sample of helium gas has a volume of 0.180L, a pressure of 0.800a and a temperature of 29 C. What is the new temp or gas of vo
Anarel [2989]

Solution:

The gas's new temperature is 604K

Justification:

Assuming standard temperature and pressure, we can determine the gas's temperature using the ideal gas law;

Step 1: Formulate the general gas law equation

P1V1/T1 = P2V2/T2

Step 2: Insert the values, converting as needed to standard units.

P1 = 0.800 atm

V1 = 0.180 L

T1 = 29°C = 273 + 29 = 302K

P2 = 3.20 atm

V2 = 90 mL = 90 * 10^-3 L = 0.09 L

Step 3: Solve for T2

The new gas temperature T2 is calculated as:

T2 = P2V2T1/(P1V1)

T2 = 3.20 * 0.09 * 302 / (0.800 * 0.180)

T2 = 86.976 / 0.144

T2 = 604K

The gas's new temperature is 604K.

7 0
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The phosphorylation of glucose to glucose 6-phosphate Group of answer choices is so strongly exergonic that it does not require
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Answer:

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Explanation:

Within glycolysis, the phosphorylation of glucose to glucose-6-phosphate occurs first, facilitated by the hexokinase enzyme. This reaction is endergonic. This phosphorylation is a coupled reaction tied to ATP hydrolysis, where the free energy released by ATP hydrolysis drives glucose phosphorylation.

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