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Natali5045456
2 months ago
10

which best explains why greg’s hands get warm as he holds a bowl of hot soup? heat energy is created from the thermal energy in

greg’s hands. heat energy is absorbed by the soup from greg’s hands. thermal energy from the soup moves to greg’s hands. thermal energy from the surrounding air moves to greg’s hands.
Chemistry
2 answers:
Tems11 [2.7K]2 months ago
5 0
The most accurate explanation for why Greg's hands warm up while holding hot soup is that the thermal energy from the soup flows into Greg's hands. Thermal energy is the kinetic energy possessed by the particles within a substance. When the hot substance (the bowl of soup) makes contact with a cooler one (Greg's hands), some kinetic energy is spontaneously transferred from the warmer substance to the cooler one. This transferred energy is termed heat energy. Heat energy can move through conduction, convection, and radiation; however, here we merely need to understand that the hot soup gives part of its thermal energy to the bowl in direct contact, which then passes some of this energy to Greg's hands, warming them.
castortr0y [3K]2 months ago
3 0
The thermal energy from the soup is transferred to Greg's hands. 
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What volume of co2 gas at 645 torr and 800. k could be produced by the decomposition of 45.0 g of caco3? caco3(s) → cao(s) + co2
KiRa [2933]
In the reaction: <span>caco3(s) → cao(s) + co2(g), it is evident that
1 mol (which is 100 g) of CaCO3 yields 1 mol (which is 44 g) of CO2
Now, the molarity of CaCO3 present in the reaction system is
</span>= \frac{weight of CaCO3 (g)}{gram molecular weight}
= \frac{45}{100} = 0.45 mol

Thus, 0.45 mol of CaCO3 leads to the formation of 0.45 mol of CO2.

According to the ideal gas equation, we have PV = nRT
V = \frac{nRT}{P}.
Considering P = 645 torr = 0.8487 atm (because 1 atm = 760 torr)
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1 month ago
HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)
Alekssandra [3086]

Answer:

Quantity of H_{2}O generated will be reduced to fifty percent of its initial amount.

Explanation:

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In accordance with the balanced equation, 1 mol of HCl interacts with 1 mol of NaOH leading to the formation of 1 mol of H_{2}O

<pif the="" quantities="" of="" reactants="" and="" hcl="" are="" diminished="" by="" half="" it="" results="" in:="">

0.5 mol of HCl interacting with 0.5 mol of NaOH yielding 0.5 mol of H_{2}O.

Consequently, it is clear that the total of H_{2}O produced will be halved if the quantities of the reactants are halved.

</pif>
5 0
3 months ago
An experimental drug, D, is known to decompose in the blood stream. Tripling the concentration of the drug increases the decompo
lions [2927]

Answer:

The rate law for the decomposition reaction is:

R=k[D]^2

The unit for the rate constant will be M^{-1}s^{-1}

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[D]'=3[D]

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[1] ÷ [2]

\frac{R}{R'}=\frac{k[D]^x}{k[D']^x}

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9=3^x

Solving for x results in:

x = 2.

This indicates a second-order reaction.

The decomposition reaction's rate law is:

R=k[D]^2

The unit for the rate constant will be:

k=\frac{R}{[D]^2}=\frac{M/s}{(M)^2}=M^{-1}s^{-1}

The unit for the rate constant will be M^{-1}s^{-1}.

5 0
2 months ago
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