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xz_007
3 months ago
12

Draw the four structures of the compounds with molecular formula C5H10O that contain a carbon-carbon double bond, an unbranched

carbon chain, and a hydroxyl group one carbon from the end of the chain.

Chemistry
1 answer:
alisha [2.9K]3 months ago
3 0

Explanation:

The molecular formula of the compound is:

The arrangement of the carbon chain within the molecule is as follows:

1. H_2C=CH-CH_2-CH_2-CH_2-OH

2. H_3C-CH=CH-CH_2-CH_2-OH

3. H_3C-CH-CH=CH-CH_2-OH

4. H_3C-CH_2-CH_2-CH=CH-OH

As there are no branches present, the valency of carbon is satisfied by 10 hydrogen atoms and 1 oxygen atom.

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At 400K both compounds are gases. At this temperature, which compound, CH4(g) or CCl4(g) , behaves more like an ideal gas
Alekssandra [3086]

Answer:

CH4

Explanation:

The ideal behavior of gases generally depends on the strength of intermolecular forces between gas molecules and whether polar bonds are present.

In the case of CCl4, polar bonds exist along with the more electronegative chlorine atom, leading to stronger intermolecular forces at 400K, as opposed to CH4 which contains only non-polar bonds.

Thus, at 400K, CH4 behaves more like an ideal gas compared to CCl4.

6 0
3 months ago
Based on the crystal-field strengths cl- < f- < h2o < nh3 < h2nc2h4nh2, which octahedral ti (iii) complex below has
eduard [2782]
<span>According to crystal field strength, the Cl ligand results in the longest d-d transition when coordinated with Ti(III) due to its classification as a weak field ligand that causes minimal d orbital splitting.</span>
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2 months ago
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