Response:
of 
can be found in 39.5 grams of .
Clarification:
Atomic weights: P= 31, F= 19,
The molar mass equals 1 atomic weight of P + 5 atomic weights of
F= 31+5 × 19
= 31+95
=126 g/mole
The number of moles in 39.5 gm of
equals 
= 
=0.3134 moles
1 mole of any substance encompasses
0.3131 moles comprises 0.3134
Thus, of can be found in 39.5 grams of .
Answer:
The original halide's formula is SrCl₂.
Explanation:
- The chemistry reaction's balanced equation is:
SrX₂ + H₂SO₄ → SrSO₄ + 2 HX, where X indicates the halide.
- Based on the equation's stoichiometry, 1.0 mole of strontium halide yields 1.0 mole of SrSO₄.
- The moles of SrSO₄ (n = mass/molar mass) = (0.755 g) / (183.68 g/mole) = 4.11 x 10⁻³ mole.
- The moles of SrX can thus be calculated as 4.11 x 10⁻³ moles based on stoichiometry from the balanced equation.
- n = mass / molar mass, thus n = 4.11 x 10⁻³ moles and mass = 0.652 g.
- The molar mass of SrX₂ is calculated using mass / n = (0.652) / (4.11 x 10⁻³ moles) = 158.62 g/mole.
- The molar mass of SrX₂ (158.62 g/mole) = Atomic mass of Sr (87.62 g/mole) + (2 x Atomic mass of halide X).
- Calculating the atomic mass of halide X, we find = (158.62 g/mole) - (87.62 g/mole) / 2 = 71 / 2 g/mole = 35.5 g/mole.
- This identifies the atomic mass of Cl.
- Consequently, the original halide's formula is SrCl₂.
Response: Water molecules migrate from the dilute to the concentrated solution
Clarification:
During osmosis, when a solution is separated by a semipermeable membrane, the solvent (commonly water) moves from the less concentrated solution, regarding solute content, through the semipermeable membrane towards the solution with a higher concentration to balance the concentration levels between the two solutions.
Thus, in this scenario, water molecules flow from the 0.4M sugar solution to the 0.7M sugar solution through the semipermeable membrane.
Answer:
2(CH3)2N2H2 + 3N2O4 → 4N2 + 4H2O + 4CO2 + heat
Explanation:
- To balance chemical equations, coefficients are assigned to both reactants and products.
- This yields an equal count of atoms of each element on both sides of the equation.
- Balancing chemical equations ensures compliance with the law of conservation of mass.
- According to this law, the mass of reactants must equal the mass of products, achievable through balancing the equation.
- The application of coefficients 2, 3, 4, 4, 4 allows for an equal balance in the equation.
- Consequently, the balanced equation can be written as:
2(CH3)2N2H2 + 3N2O4 → 4N2 + 4H2O + 4CO2 + heat
