Dalton needs to prepare a close-out report for his project. Which part of the close-out report would describe
1 answer:
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Response:
The cutting speed is calculated at 365.71 m/min
Clarification:
Given parameters include
diameter D = 250 mm
length L = 625 mm
Feed f = 0.30 mm/rev
cut depth = 2.5 mm
n = 0.25
C = 700
To find
the cutting speed that ensures the tool life coincides with the cutting time for the three parts
The formula for cutting time is given as
Tc =
....................1where D refers to diameter, L refers to length and f refers to feed while V represents speed
Tc =
Tc =
Given the tool life is expressed as
T = 3 × Tc............................2
where T denotes tool life and Tc is the cutting duration
Calculating tool life by substituting values into equation 2 yields
T = 3 ×
This yields V = 365.71
Thus, the cutting speed calculates to 365.71 m/min
Answer:
a) , b)
Explanation:
a) The uniform dresser can be modeled using specific equilibrium equations:
Following some algebraic manipulations, the formulated equation is derived:
b) Similarly, the man can be represented by a set of equilibrium equations:
After some algebraic changes, the expression for the coefficient of static friction comes out as:
Answer:
Explanation:
A liquid food containing 12% total solids is heated via steam injection at a pressure of 232.1 kPa (see Fig. E3.3). The product starts at a temperature of 50°C and has a flow rate of 100 kg/min, being elevated to a temperature of 120°C. The specific heat of the product varies with its composition as follows:
and the
specific heat of the product at 12% total solids is 3.936 kJ/(kg°C). The goal is to calculate the quantity and minimum quality of steam required to ensure that the leaving product has 10% total solids.
Given
Product total solids in () = 0.12
Product mass flow rate () = 100 kg/min
Product total solids out () = 0.1
Product temperature in () = 50°C
Product temperature out () = 120°C
Steam pressure = 232.1 kPa at () = 125°C
Product specific heat in () = 3.936 kJ/(kg°C)
The mass equation is:
Also
Therefore:
The energy balance equation is:
kJ/(kg°C)
By substituting values into the energy equation:
From the properties of saturated steam at 232.1 kPa,
= 524.99 kJ/kg
= 2713.5 kJ/kg
% quality =
Any steam quality above 63.5% will result in higher total solids in the heated product.