For the first-order decomposition, the equation is: ln(x0 / x) = kt. At t = 200, x = 0.0300 M, we have ln(x0 / 0.03) = 200k. At t = 400, when x = 0.0200 M, we utilize ln(x0 / 0.02) = 400k. By multiplying the first equation by 2, we get 2ln(x0 / 0.03) = 400k, which aligns with the second equation, leading us to conclude that 2ln(x0 / 0.03) = ln(x0 / 0.02). This suggests (x0 / 0.03)^2 = x0 / 0.02, allowing us to find x0 = 0.045 M as the initial concentration. Plugging this back into the first equation yields: ln(0.045 / 0.03) = 200k, from which it follows that k = 0.0020273 (rate constant). The half-life can be calculated with x = 0.5x0: ln(x0 / 0.5x0) = 0.0020273t, resulting in ln(2) = 0.0020273t, which simplifies to t = 341.90 minutes (half-life).
Answer: These celestial bodies are composed of rock or gas and are named after ancient deities.
Explanation:
Earth is the THIRD planet from the Sun and is capable of sustaining life for various organisms.
VENUS ranks as the second planet in our solar system and derives its name from the Roman goddess associated with love and beauty.
MARS, the fourth planet, gets its name from the Roman goddess of war.
Hence, Venus and Mars are NEIGHBORS to EARTH.
Answer:
When HBCG and BCG^- are at the same concentration, the resulting color is green. This green shade initially becomes visible at a pH of 3.8.
Explanation:
HBCG serves as an indicator formed by dissolving solids in ethanol.
Since
Ka=[BCG−][H3O+][HBCG] When [BCG-] equals [HBCG], it follows that Ka = [H3O+].
<pWith a pH of 3.8,<pKa= [H3O+] = -antilog pH = -antilog (3.8)
Ka= 1.58 ×10^-4
Response:
Clarification:
refer to the solution provided below
