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Nadya
1 month ago
14

1. Susie wondered if the height of a hole punched in the side of a quart-size milk carton would affect how far from the containe

r a liquid would spurt when the carton was full of the liquid. She used 4 identical cartons and punched the same size hole in each. The hole was placed at a different height on one side of each of the containers. The height of the holes varied in increments of 5 cm, ranging from 5-20 cm from the base of the carton. She put her finger over the holes and filled the cartons to a height of 25 cm with a liquid. When each carton was filled the proper level, she placed it in the sink and removed her finger. Susie measured how far away from the carton’s base the liquid had squirted when it hit the bottom of the sink.
Hypothesis:
Independent Variable:
Dependent Variable:
Constant (at least one):
Control:
Number of groups:
Number of trials per group:
Physics
2 answers:
Sav [3.1K]1 month ago
7 0
Hypothesis: The liquid will project far.
Independent Variable: Height of the hole.
Dependent Variable: Distance of the squirt.
Constant: All other factors aside from the independent variable, such as the liquid volume.
Control: None that I recognize.
Number of groups: 4
Trials per group: 4
kicyunya [3.2K]1 month ago
6 0

Response:

An experiment is conducted to verify a hypothesis, which is an expected explanation of a natural occurrence grounded in earlier studies.

The design of the experiment needs to incorporate three variable types: the variable that can be adjusted (independent variable), the one that is measured (dependent variable), and the factor that remains unchanged throughout the trial (constant variable).

The sample is split into two groups: the experimental group that contains the key factor being examined and the control group that does not.

In this scenario,

1. Hypothesis: Liquid spurts when it falls from a height.

2. Independent Variable: Variations in the height of the hole.

3. Dependent Variable: The distance the liquid squirts.

4. Constant (at least one): The amount of liquid used is held steady.

5. Control: Four identical cartons, each with an equally sized hole.

6. Number of groups: Two (control and experimental).

7. Number of trials per group: Four.

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A 54 kg man holding a 0.65 kg ball stands on a frozen pond next to a wall. He throws the ball at the wall with a speed of 12.1 m
serg [3582]

Response:

The man's speed is 0.144 m/s

Explanation:

This exemplifies conservation of momentum.

The momentum of the ball prior to being caught must equal the momentum of the man-ball system after catching the ball.

Mass of the ball = 0.65 kg

Mass of the man = 54 kg

Speed of the ball = 12.1 m/s

The momentum of the ball before impact can be calculated as mass multiplied by velocity

= 0.65 x 12.1 = 7.865 kg-m/s

After catching the ball, the momentum of the combined system is

(0.65 + 54)Vf = 54.65Vf

Where Vf denotes their final shared velocity.

Setting the initial momentum equal to the final momentum,

7.865 = 54.65Vf

Vf = 7.865/54.65 = 0.144 m/s

4 0
11 days ago
How many times could Haley fly bewteen the two flowers in 1 minute (60 seconds)​
Yuliya22 [3333]
The answer is 30 seconds.
7 0
26 days ago
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tas watches as his uncle changes a flat tire on a car. his uncle raises the car using a machine called a jack. each time his unc
Softa [3030]

The answer is

-Small f and large D.

The explanation:

-A car jack acts as a machine, defined as an apparatus that aids individuals in exerting force more easily.

-Hence, by applying a small force to the jack, the height at which the car is elevated increases.

Machines are essential for people to amplify their strength; without them, lifting a car would be impossible.

Employing leverage or hydraulic principles, machines enhance your exerted force.

Utilizing a greater lever allows for extensive movement with minimal force, resulting in the opposite side moving shorter distances with an increased force.

7 0
1 month ago
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1)After catching the ball, Sarah throws it back to Julie. However, Sarah throws it too hard so it is over Julie's head when it r
Softa [3030]

Answer:

1)

v_{oy}=11.29\ m/s

2)

y=7.39\ m

Explanation:

Projectile Motion

When an object is projected near the surface of the Earth at an angle \theta to the horizontal, it follows a trajectory known as a parabola. The only force acting on it (ignoring wind resistance) is gravity, affecting the vertical axis.

The height of a projectile can be calculated using

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

where y_o represents the initial height from ground level, v_{oy} is the vertical component of the initial velocity, and t is the elapsed time.

The vertical speed component is expressed as

v_y=v_{oy}-gt

1) To proceed, we will determine the initial vertical velocity component since we lack sufficient data to calculate the absolute value of v_o.

The peak height is attained when v_y=0, which allows us to compute the time to reach that height.

v_{oy}-gt_m=0

Solving for t_m

\displaystyle t_m=\frac{v_{oy}}{g}

Thus, the maximum height reached is

\displaystyle y_m=y_o+\frac{v_{oy}^2}{2g}

We know this value is equal to 8 meters

\displaystyle y_o+\frac{v_{oy}^2}{2g}=8

Continuing with the calculations for v_{oy}

\displaystyle v_{oy}=\sqrt{2g(8-y_o)}

Substituting known values yields

\displaystyle v_{oy}=\sqrt{2(9.8)(8-1.5)}

\displaystyle v_{oy}=11.29\ m/s

2) At t=1.505 seconds, the ball is positioned above Julie’s head; we can calculate

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

\displaystyle y=1.5+(11.29)(1.505)-\frac{9.8(1.505)^2}{2}

\displaystyle y=1.5\ m+16,991\ m-11.098\ m

y=7.39\ m

5 0
1 month ago
If you secure a refrigerator magnet about 2mmfrom the metallic surface of a refrigerator door and then move the magnet sideways,
Yuliya22 [3333]

Response:

(A) 4* 6 ^ ⁻6 T m² (B) 2 * 10 ^ ⁻6 v

Clarification:

Solution

Given that:

A refrigerator magnet with a depth of approximately 2 mm

The estimated magnetic field strength of the magnet is = 5 m T

The Area = 8 cm²

Now,

(A) The magnetic flux ΦB = BA

Therefore,

ΦB = (5 * 10^⁻ 3) ( 4 * 10 ^⁻2) * ( 2 * 10^ ⁻2) Tm²

Thus,

ΦB = 4* 6 ^ ⁻6 T m²

(B) By employing Faraday's Law, the subsequent equation applies:

Ε = Bℓυ

Where,

ℓ = 2 cm equals 2 * 10 ^⁻2 m

B = 5 m T = 5 * 10 ^ ⁻3 T

υ = 2 cm/s = 2 * 10 ^ ⁻2 m/s

Therefore,

Ε = (5 * 10 ^ ⁻3 T) * (2 * 10 ^ ⁻2) (2 * 10 ^ ⁻2) v

E =2 * 10 ^ ⁻6 v

7 0
21 day ago
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