Answer:
Explanation:
Considering that,
The mass of the first vehicle
M1= 328kg
It is traveling in the positive x direction at a speed of
U1 = 19.1m/s
The speed of the second vehicle
U2 = 13m/s, moving in the same direction as the first vehicle..
The mass of the second vehicle
M2 = 790kg
The speed of the second vehicle post-collision
V2 = 15.1 m/s
The speed of the first vehicle following the collision
V1 =?
This represents an elastic collision,
and applying the principle of conservation of momentum
The momentum prior to the collision must equal the momentum afterwards
P(before) = P(after)
M1•U1 + M2•U2 = M1•V1 + M2•V2
328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1
16534.8 = 328•V1 + 11929
328•V1 = 16534.8—11929
328•V1 = 4605.8
V1 = 4605.8/328
V1 = 14.04 m/s
The speed of the first vehicle after the collision is 14.04 m/s