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FrozenT
2 months ago
5

How many liters of a 0.225 M solution of KI are needed to contain 0.935 moles of KI?

Chemistry
1 answer:
alisha [2.9K]2 months ago
6 0
The result is 4.16 L. Based on the provided information, we calculated the following: Molarity = 0.225 M, Quantity of KI = 0.935 moles, To find Volume: Molarity = moles/Volume, hence Volume = moles/Molarity. Thus, Volume = 0.935/0.225, giving Volume = 4.16 L. Consequently, 4.16 L of KI is required.
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Explanation:

The optical phenomenon would nearly resemble, yet be entirely distinct from, that involved with the exploitation of light. Interference and diffraction are the characteristics distinguishing waves from particles: waves can interfere and disperse, whereas particles cannot.

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2 months ago
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