Number pattern Write a recursive method called print Pattern() to output the following number pattern. Given a positive integer

Question

max2010maxim

19 days ago

8

Number pattern Write a recursive method called print Pattern() to output the following number pattern. Given a positive integer

as input (Ex: 12), subtract another positive integer (Ex: 3) continually until 0 or a negative value is reached, and then continually add the second integer until the first integer is again reached.

Engineering

2 answers:

mote1985 [204] · Answer 1 · 2026-03-07T14:39:04+03:00

Response:

import java.util.Scanner;

public class NumberPattern {

public static void decrement(int num1, int num2)

{

if(num1 < 0)

return;

System.out.print(num1 + " ");

decrement(num1 - num2, num2);

}

public static void increment(int num1, int num2)

{

int current = num1 - ((num1 / num2) * num2);

current = current + num2;

begin(num1, num2, current);

}

public static void begin(int num1, int num2, int current)

{

if(current > num1)

return;

System.out.print(current + " ");

begin(num1, num2, current + num2);

}

public static void displayNumPattern(int num1, int num2)

{

decrement(num1, num2);

increment(num1, num2);

}

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

displayNumPattern(num1, num2);

}

Clarification:

alex41 [274] · Answer 2 · 2026-03-07T14:41:01+03:00

Response:

Refer to the explanation

Clarification:

Code:

import java.util.Scanner;

public class NumberPattern {

public static int x, count;

public static void displayNumPattern(int num1, int num2) {

if (num1 > 0 && x == 0) {

System.out.print(num1 + " ");

count++;

displayNumPattern(num1 - num2, num2);

} else {

x = 1;

if (count >= 0) {

System.out.print(num1 + " ");

count--;

if (count < 0) {

System.exit(0);

}

displayNumPattern(num1 + num2, num2);

}

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

displayNumPattern(num1, num2);

}

See attached example output