Answer:

Explanation:
The stone reaches the top of the flagpole at both t = 0.5 s and t = 4.1 s
therefore, the total duration of the upwards motion above the peak of the pole is provided as

now we have



this indicates the speed at the flagpole's top
at this point we have



the height of the flagpole is stated as



Answer:
Explanation:
a) La fuerza neta que actúa sobre la caja en la dirección vertical es:
Fnet=Fg−f−Fp *sin45 °
aquí Fg representa la fuerza gravitacional, f es la fuerza de fricción, y Fp es la fuerza de empuje.
Fnet=ma
ma=Fg−f−Fp *sin45 °
a=
=0.24 m/s²
Vf =Vi +at
=0.48+0.24*2
Vf=2.98 m/s
b)
Fnet=Fg−f−Fp *sin45 °
=Fg−0.516Fp−Fp *sin45 °
=30-1.273Fp
Fnet=0 (Ya que la velocidad es constante)
Fp=30/1.273
=23.56 N
Answer:
d) v1 = v2 = v3
Explanation:
This can be determined through the principle of energy conservation. We assess the total mechanical energy E=K+U (the sum of kinetic energy and gravitational potential energy) at both the initial and final positions, ensuring they remain constant.
<pInitially, for the three spheres, we have:

Finally, for the three spheres, we see:

<pGiven that

, and since

remains identical for all spheres, it follows that

is identical for all spheres, indicating that

, the final velocity, is equal for each ball.
Answer:

Explanation:
The beacon is rotating at an angular speed of

so we have



We know that

At this point we have


So we can conclude with


Answer:
The initially bent young tree has been straightened by adjusting the tensions of the three guy wires to AB = 7 lb, AC = 8 lb, and AD = 10 lb. Please calculate the force and moment reactions at the trunk's base point O, disregarding the weight of the tree.
C and D are situated 3.1' from the y-axis, while B and C are located 5.4' from the x-axis, and A has a height of 5.2'.
Explanation:
Refer to the attached image.