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Ronch
1 month ago
12

If 3.18 x 10^23 atoms of iron react with 67.2 L of chlorine gas at STP, what is the maximum

Chemistry
1 answer:
Tems11 [2.7K]1 month ago
3 0

84.34 grams of iron (III) chloride is the maximum produced since iron is the limiting reagent, and chlorine gas is in excess.

Explanation:

Balanced equation:

2 Fe + 3 Cl2 → 2 FeCl3​

DATA PROVIDED:

iron =  atoms

mass of chlorine = 67.2 liters

mass of FeCl3 =?

The number of moles of iron will be calculated as

number of moles = \frac{total number of atoms}{Avagaro's number}

number of moles = \frac{3.18 x 10^23}{6.022x 10^23}

number of moles = 0.52 mol of iron

moles of chlorine gas

number of moles = \frac{mass}{molar mass of 1 mole}

Substituting the values into the equation:

n = \frac{67200}{70.96}               (molar mass of chlorine gas = 70.96 g/mol)

   = 947.01 moles

As iron is the limiting reagent therefore

2 moles of Fe lead to 2 moles of FeCl3

0.52 moles of Fe will yield

\frac{2}{2} = \frac{x}{0.52}

0.52 moles of FeCl3 is produced.

To express this in grams:

mass = n x molar mass

         = 0.52 x 162.2                   (molar mass of FeCl3 is 162.2g/mol)  

          = 84.34 grams        

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Answer:

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Explanation:

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SrX₂ + H₂SO₄ → SrSO₄ + 2 HX, where X indicates the halide.

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Answer:

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