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mafiozo
2 months ago
9

HELP!!! Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = 4 cos 3θ

Mathematics
2 answers:
Zina [12.3K]2 months ago
6 0

Response:

                The graph exhibits symmetry concerning the x-axis.

Step-by-step outline:

  • Symmetry about the polar axis (x-axis) is observed when replacing (r,θ) with (r,-θ), resulting in an equation identical to the original.
  • For the y-axis, replacing (r,θ) with (-r,-θ) gives the same equation as the original.
  • For symmetry around the pole (origin), a switch of (r,θ) to (-r,θ) must yield the same original equation.

We have the following equation:

           r=4\cos 3\theta

  • When substituting (r,θ) with (r,-θ), the result is:

r=4\cos 3(-\theta)\\\\i.e.\\\\r=4\cos (-3\theta)\\\\i.e.\\\\r=4\cos 3\theta

(  Since, we are aware that:

\cos (-\tehta)=\cos \theta  )

Therefore, the graph is symmetric with respect to the x-axis.

  • For when we substitute (r,θ) with (-r,-θ)

-r=4\cos 3(-\theta)\\\\i.e.\\\\-r=4\cos (-3\theta)\\\\i.e.\\\\-r=4\cos 3\theta\\\\i.e.\\\\r=-4\cos 3\theta

In this case, we see that the graphs are not equivalent upon performing this substitution.

Consequently, the graph lacks symmetry concerning the y-axis.

  • Upon substituting (r,θ) with (-r,θ), we find:

-r=4\cos 3\theta\\\\i.e.\\\\r=-4\cos 3\theta

Again, it's clear that the resulting graphs do not equate.

Thus, the graph does not exhibit symmetry with respect to the pole (origin).[TAG_63]]

Leona [12.6K]2 months ago
3 0
To evaluate y-symmetry, let’s define r = 5 cos 3θ and set <span>θ=π−θ</span> which implies that <span><span><span>r=5cos3θ</span><span>θ=(π−θ)</span><span>r=5cos(3(π−θ))⟹r=5cos(3π−3θ)</span></span></span>
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Step-by-step explanation:

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In inverse relationships, as one measure increases, the other decreases.

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Second step: handle 1750 mg

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The equation for z is:

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Here, x is the value being evaluated, m denotes the mean, and sd represents the standard deviation.

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