The amount of heat needed to elevate an object's temperature can be determined using the formula,
heat = mass x specific heat x (T2 - T1)
Thus, specific heat can be found with the following formula,
specific heat = heat / (mass x (T2 - T1))
By substituting,
specific heat = 645 J / ((28.4 g)(15.5 - - 11.6))
The calculated specific heat from the above equation is 0.838 J/g°C.
The density is 1.03 g/cm³.
Explanation: The density of a substance is calculated with the formula:
1 kg = 1000 g therefore 2.06 kg = 2060 g.
1 L = 1000 cm³ thus 2 L = 2000 cm³.
We now find:
Mass = 2060 g
Volume = 2000 cm³.
Thus, the final answer of density is:
1.03 g/cm³.
I hope this information assists you.
Answer:
Explanation:
1) Alkali metals and halogens both need to achieve a stable outer electron shell, requiring alkali metals to lose one electron and halogens to gain one.
2) They share an identical count of outer shell electrons.
3) Typically, they have elevated melting points.
4) They exhibit low reactivity or none at all.
5) They belong to group 7.
<span>BaCl2 + Na2SO4 --> BaSO4 + 2NaCl
In this reaction, 1.0 g of BaCl2 and 1.0 g of Na2SO4 are present. We need to identify the limiting reactant.
"First, convert grams to moles"
1.0 g BaCl2 * (1 mol BaCl2 / 208.2 g BaCl2) = 4.8 x 10^-3 mol BaCl2
1.0 g Na2SO4 * (1 mol Na2SO4 / 142.04 g Na2SO4) = 7.0 x 10^-3 mol Na2SO4
(7.0 x 10^-3 mol Na2SO4 / 4.8 x 10^-3 mol BaCl2) = 1.5 mol Na2SO4 per mol BaCl2
"Using this ratio to compare with the balanced equation, BaCl2 + Na2SO4 --> BaSO4 + 2NaCl"
The balanced equation indicates that 1 mol of BaCl2 reacts with 1 mol of Na2SO4. However, we found that 1.5 mol of Na2SO4 is available for each mol of BaCl2. Therefore, BaCl2 is the limiting reagent.</span>
Each isotope contains an identical number of protons and electrons, but they vary in neutron count, making them isotopes.
