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Aloiza
11 days ago
15

Calculate how many grams of the product form when 16.7 g of liquid bromine reacts with solid potassium. Assume that there is mor

e than enough of the solid potassium. 2 K(s) + Br2(l) → 2 KBr(s)
Chemistry
1 answer:
Anarel [2.5K]11 days ago
4 0
49.7 grams of the product will be produced. Explanation: According to Avogadro's law, a mole of any substance occupies 22.4 liters under standard temperature and pressure and contains Avogadro's number of particles. To find the number of moles, we utilize the relevant equations. The limiting reagent here is Br_2 as it constrains the product's formation since potassium is ample. Following stoichiometric principles, 1 mole of Br_2 reacts to yield 2 moles of KBr, thus 0.21 moles of Br_2 will convert into \frac{2}{1}\times 0.21=0.42 moles of the product. Consequently, 49.7 grams of that product will be generated.
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If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
VMariaS [2649]

Answer:

The heat capacity of the calorimeter is C_c = 54.4 \frac{J}{c}

Explanation:

Given the data

Heat supplied Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Change in temperature = ΔT = 35.82 - 24.58 = 11.24 °C

From the conditions provided

Q = m_w C_w ΔT + C_c ΔT

Plugging all values into the above equation yields

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This represents the heat capacity of the calorimeter.

7 0
25 days ago
If 500.0 mL of 0.10 M Ca2+ is mixed with 500.0 mL of 0.10 M SO42−, what mass of calcium sulfate will precipitate? Ksp for CaSO4
Anarel [2580]

Answer:

The amount of calcium sulfate that precipitates is 6.14 grams.

Explanation:

Step 1: Provided data

We are mixing 500.0 mL of 0.10 M Ca^2+ with 500.0 mL of 0.10 M SO4^2−

The Ksp for CaSO4 is 2.40×10^−5.

Step 2: Determine moles of Ca^2+

Moles of Ca^2+ = Molarity of Ca^2+ * Volume

Moles of Ca^2+ = 0.10 * 0.500 L

Moles of Ca^2+ = 0.05 moles

Step 3: Determine moles of SO4^2-

Moles of SO4^2- = 0.10 * 0.500 L

Moles SO4^2- = 0.05 moles

Step 4: Compute total volume

Total volume = 500.0 mL + 500.0 mL = 1000 mL = 1L

Step 5: Compute Q

Q = [Ca2+] [SO42-]

[Ca2+] = 0.050 M and [SO42-]

Qsp = (0.050)(0.050) = 0.0025 >> Ksp

This indicates that precipitation will take place.

Step 6: Calculate molar solubility

Ksp = 2.40 * 10^-5 = [Ca2+][SO42-] =(x)(x)

2.40 * 10^-5 = x²

x = √(2.40 * 10^-5)

x = 0.0049 M (molar solubility)

Step 7: Determine total dissolved CaSO4

Total CaSO4 dissolved = 0.0049 M * 1 L * 136.14 g/mol = 0.667 g

Step 8: Calculate initial mass of CaSO4

Initial moles of CaSO4 = 0.050

Initial mass of CaSO4 = 0.050 * 136.14 g/mol

Initial mass of CaSO4 = 6.807 grams

Step 9: Calculate precipitate mass

6.807 - 0.667 = 6.14 grams.

The mass of calcium sulfate that will emerge as a precipitate is 6.14 grams.

5 0
26 days ago
As part of an investigation, students combined substances in a beaker to observe chemical reactions. They performed two procedur
lorasvet [2495]

Response:

D.

Justification:

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The issue with your setup is that the surface where you placed the drop is contaminated or dirty, preventing it from being wetted by the solution. To fix this, thoroughly clean the surface before applying the drop.

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