Answer:
Please include the diagrams and repost them.
Answer:
Δx=(v+v0/2)t
Explanation:
We can determine which kinematic equation to apply by selecting the one that encompasses the known variables as well as the unknown we aim to solve for.
In this scenario, the unknown we wish to determine is the initial velocity v_0v
0
v, start subscript, 0, end subscript of the roller coaster.
Explanation:
We are given that,
Mass of the rocket, 
(a) The standard unit of mass is kilogram (kg). The conversion between slugs and kilograms is as follows:
1 slug = 14.59 kg
Thus, 
Mass of the rocket, m = 3647500 kg
(b) The weight of the rocket can be expressed as:
W = m g
or
(c) If the rocket were on the moon, the gravitational acceleration on the moon is given as 
Mass refers to the quantity of matter present in an object. Therefore, the mass of the rocket remains constant at 3647500 kg
The weight of the rocket on the moon would be, 
W = 5872475 N
or
Thus, this is the final answer required.
Given
m1(mass of red bumper): 225 Kg
m2 (mass of blue bumper): 180 Kg
m3(mass of green bumper): 150 Kg
v1 (velocity of red bumper): 3.0 m/s
v2 (final velocity of the combined bumpers):?
The principle of momentum conservation indicates that the momentum before impacts equals the momentum after impacts. This can be represented mathematically as:
Pa= Pb
Pa symbolizes the momentum prior to collision and Pb refers to momentum after collision.
Applying this principle to the aforementioned scenario results in:
Momentum pre-collision= momentum post-collision.
Momentum pre-collision = (m1+m2) x v1 =(225+180)x 3 = 1215 Kgm/s
Momentum post-collision = (m1+m2+m3) x v2 =(225+180+150)x v2
=555v2
We now know that Momentum pre-collision equals momentum post-collision.
<presulting in="">
1215 = 555 v2
v2 = 2.188 m/s
Consequently, the final velocity of the combined bumper cars is 2.188 m/s
</presulting>
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