Satellite X exhibits both a longer period and a reduced tangential speed compared to Satellite Y.
Answer:
a) Ф = 0.016 N / C m, b) q_{int} = 0.14 10⁻¹² C
Explanation:
a) For this scenario, we rely on Gauss's law
Ф = E.ds =
/ε₀
As the field points in the x direction, there is no flux through the cylinder walls.
Ф = E A
The area of a circle is
A = π r
Ф = E π r
Ф = (x- 3.6) r
Now, let's compute
Ф = (3.7 -3.6) 0.16
Ф = 0.016 N / C m
b) Using Gauss's law, we have
q_{int} = Ф ε₀
Where the flow is present on both sides, at the face corresponding to x = 0, the flow is zero
q_{int} = 0.016 8.85 10⁻¹²
q_{int} = 0.14 10⁻¹² C
Answer:

Explanation:
Given,
Voltage of the primary coil (V_p) = 30 kV-rms
Voltage of the secondary coils (V_s) = 345 kV-rms
number of turns in the primary coil (n_p) = 80 turns
number of turns in the secondary coil (n_s) =?
the ratio of turns between primary and secondary coils






The number of turns in the secondary coil is equal to 
Response:
In this scenario, the refractive index of seawater is 1.33, while the index for air is 1. Because of this, the refraction angle is smaller than the angle of incidence, making the fish appear closer
Conversely, when viewed from the fish's perspective looking at a person's face, the angle has increased, making the person appear further away
Clarification:
This discussion is analyzed by applying the refraction law, which states that when a light ray crosses from one medium to another, its path bends due to differing indices of refraction,[ [TAG_20]]
n₁ sin θ₁ = n₂ sin θ₂
where n₁ and n₂ are the refractive indices and θ represents the angles for each medium.
Here, with seawater being 1.33 and air at 1, the refraction angle remains lesser than the angle of incidence, leading to the fish appearing nearer
1 sin θ₁ = 1.33 sin θ₂
θ₂ = sin⁻¹ ( 1/1.33 sin θ₁)
When the fish gazes at the human face, the angle's reason increases, hence making the face seem more distant