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zheka24
3 months ago
11

An airplane cruises at 850 km/h relative to the air. It is flying from Denver, Colorado, due west to Reno, Nevada, a distance of

1200 km, and will then return. There is a steady 90km/h wind blowing to the east.
Physics
1 answer:
Yuliya22 [3.3K]3 months ago
8 0

Answer:

the difference in flight duration= 0.3023 hours

Explanation:

The question details are lacking, but I located it within your textbook.

Aircraft speed = 850 km/h

Wind speed against the aircraft = 90 km/h

As a result, the effective speed flying west = 850 - 90 = 760 km/hr

Distance traveled = 1200 km

time required = distance/speed = 1200/760 = 1.5789 hours

Returning, wind speed complements aircraft speed, thus

net speed for return journey = 850 + 90 = 940 km/hr

time taken for return = 1200/940 = 1.2765 hours

Consequently, the difference in flight duration= 1.5789 - 1.2765 = 0.3023 hours

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Which, if any, of the following statements concerning the work done by a conservative force is NOT true? All of these statements
Yuliya22 [3333]

Answer:

If the starting and ending points are identical, the overall work equals zero.

Explanation:

Option (D) is correct.

A force is considered conservative when the work performed by it while moving an object from point A to point B does not rely on the path taken and remains consistent across all paths. The work done is determined solely by the initial and final locations of the particle. Thus, when the initial and final positions in a conservative field coincide, the work is said to be zero.

8 0
4 months ago
An electric buzzer is activated, then sealed inside a glass chamber. When all of the air is pumped out of the chamber, how is th
ValentinkaMS [3465]
The intensity of the sound increases because sound waves are mechanical waves, meaning they cannot move through a vacuum and require a medium to propagate.
4 0
3 months ago
When a vertical beam of light passes through a transparent medium, the rate at which its intensity I decreases is proportional t
Keith_Richards [3271]

Response:

The intensity of light 18 feet underwater is about 0.02%

Clarification:

Employing Lambert's law

Let dI / dt = kI, where k is a proportionality factor, I represents the intensity of incident light, and t indicates the thickness of the medium

Then dI / I = kdt

Taking logarithms,

ln(I) = kt + ln C

I = Ce^kt

At t=0, I=I(0) implies C=I(0)

I = I(0)e^kt

At t=3 & I=0.25I(0), we find 0.25=e^3k

Solving for k gives k = ln(0.25)/3

k = -1.386/3

k = -0.4621

I = I(0)e^(-0.4621t)

I(18) = I(0)e^(-0.4621*18)

I(18) = 0.00024413I(0)

The intensity of light 18 feet underwater is about 0.2%

3 0
3 months ago
A loop of wire with cross-sectional area 1 m2 is inserted into a uniform magnetic field with initial strength 1 T. The field is
serg [3582]

Answer:

La magnitud del EMF es 0.00055  volts

Explanation:

El EMF inducido es proporcional al cambio en el flujo magnético según la ley de Faraday:

emf\,=-\,N\, \frac{d\Phi}{dt}

Como en nuestro caso hay solo un lazo de alambre, entonces N=1 y obtenemos:

emf\,=-\,N\, \frac{d\Phi}{dt}

Necesitamos expresar el flujo magnético dada la geometría del problema;

\Phi=B\,\,Adonde A es el área de la bobina que permanece constante con el tiempo, y B es el campo magnético que cambia con el tiempo. Por lo tanto, la ecuación para el EMF se convierte en:

emf\,=-\,N\, \frac{d\Phi}{dt} = \frac{d\Phi}{dt} =-\frac{d\,(B\,A)}{dt} =-\,A\,\frac{d\,(B)}{dt}=- 1\,m^2(2\,\,T/h})= -2\,\,m^2\,T/(3600\,\,s)= -0.00055\,Volts

8 0
2 months ago
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