A metallic object holds a charge of −4.8 × 10−6 C. What total number of electrons does this represent? (e = 1.6 × 10−19 C is the

Question

4 months ago

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magnitude of the electronic charge.)

1 answer:

Anarel [2.9K] · Answer 1 · 2026-02-20T18:41:37+03:00

5 0

Answer:

$n=3.0\times 10^{13}$

Explanation:

Charge of one electron = $-1.6\times 10^{-19}\ C$

The formula for calculating charge is:

$Charge=n\times q_e$

Given that: Charge = $-4.8\times 10^{-6}\ C$

$-4.8\times 10^{-6}=n\times (-1.6\times 10^{-19})$

$n=\frac{4.8\times 10^{-6}}{1.6\times 10^{-19}}=3.0\times 10^{13}$

Total electrons, n = $3.0\times 10^{13}$