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Allushta
24 days ago
14

Find an expression for the electric field E⃗ at the center of the semicircle. Hint: A small piece of arc length Δs spans a small

angle Δθ=Δs /R, where R is the radius. Express your answer in terms of the variables Q, L, unit vectors i^, j^, and appropriate constants.
Physics
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A ball collides elastically with an immovable wall fixed to the earth’s surface. Which statement is false? 1. The ball's speed i
Maru [3345]

Answer:

Statements 4, 6 & 7 are incorrect.

Explanation:

In any elastic collision, the overall momentum vector sum of the system remains zero.

In this scenario, an elastic collision occurs between the ball and a stationary wall. The ball's velocity will consistently revert after the impact, leading to a change in direction of momentum.

The initial momentum of the ball is represented as:

p=m.v

where:

m = mass of the ball

v = initial velocity of the body

post-collision for the elastic interaction:

p=m.(-v)

  • Here, the momentum changes solely in direction, thus contradicting statement 7.
  • During the impact, both the ball and the wall exert forces on each other that are equal and opposite. The wall remains motionless, while the ball is influenced by the wall's reaction force, performing work on it, which contradicts statement 4.
  • Given that this collision is elastic, the ball's form and dimensions do not alter.
  • The previous points clearly indicate that not all provided statements hold true, thus violating statement 6.
4 0
2 months ago
When you skid to a stop on your bike, you can significantly heat the small patch of tire that rubs against the road surface. Sup
Sav [3153]

Answer:

W_f = 148.17J

Explanation:

The friction created between the tire and the ground generates thermal energy as force is applied during skidding.

The mentioned force relates to half the impact on the rear tire, resulting in a calculated normal force of,

N=\frac{mg}{2} = \frac{90*9.8}{2} = 441N

The work executed is determined by the frictional force and the distance covered,

W_f = fd = \mu_k Nd

Where \mu_k [/ tex] is the coefficient of kinetic frictionN is the normal force previously found d is the distance traveled,Replacing,[tex]W_f = (0.80)(441)(0.42)

The thermal energy produced from the work done is,

W_f = 148.17J

3 0
3 months ago
Part a consider another special case in which the inclined plane is vertical (θ=π/2). in this case, for what value of m1 would t
serg [3582]

The solution leads to the conclusion that m1 = m2

For mass m1, the force balance in the y direction equals zero:
0 = T - m1*g
Rearranging gives:
m1*g = T

For mass m2, the force balance in the y direction equals zero:
0 = T - m2*g
Rearranging provides:
m2*g = T

Setting these two equal allows us to solve for m1:
m1*g = m2*g

= m1 = m2

 

Explanation:

The force acting on each individual mass pulls down while the tension created by the other mass exerts an upward force due to the operation of the pulley system, resulting in balanced forces on both masses.

6 0
3 months ago
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