evaluate the numerical value of the vertical velocity of the car at time t=0.25 s using the expression from part d, where y0=0.7

Question

2 months ago

10

5m, α=0.95s^-1, and w=6.3s^-1

1 answer:

Ostrovityanka [3.2K] · Answer 1 · 2026-02-16T10:18:20+03:00

Given :

Displacement , y = 0.75 m .

Angular acceleration , $\alpha=0.95\ s^{-2}$ .

Initial angular velocity , $\omega_o=6.3\ s^{-1}$ .

To Find :

The vertical velocity after t = 0.25 s .

Solution :

Using the circular motion equation:

$\omega=\omega_o+\alpha t$

Substituting the provided values results in:

$\omega=6.3+0.95\times 0.25\\\\\omega= $$6.5375\ s^{-1}$

The vertical velocity can be derived as:

$v=y\omega\\\\v=0.75\times 6.5375\ m/s\\\\v=4.90\ m/s$

Consequently, the vertical velocity of the car at time t=0.25 s is calculated to be 4.90 m/s .

This concludes the required solution.