The kangaroo reaches a maximum vertical altitude of 2.8 m, which can be calculated using the formula 2.8 = 1/2 * 9.8 * t^2. Thus, applying the equation s = ut + 1/2at^2.
1) The projectile's motion follows
,

In order to determine the velocity, we must compute the derivative of h(t):
Next, we will compute the speed at t=2 s and t=4 s:
The negative value of the second speed suggests that the projectile has already attained its highest point and is now descending.
2) The maximum height of the projectile occurs when its speed equals zero:
Thus, we have
And solving yields

3) To determine the maximum height, we substitute the time at which the projectile reaches this peak into h(t), specifically t=2.30 s:
4) The time at which the projectile lands is when the height reaches zero; h(t)=0, which leads to
This results in a second-degree equation, producing two answers: the negative root can be disregarded as it lacks physical significance; the second root is

, which indicates the landing time of the projectile.
5) The moment the projectile impacts the ground corresponds to the velocity at time t=4.68 s:

, carrying a negative sign to denote a downward direction.
Answer:
B=
≅8.06
Explanation:
Applying the Pythagorean theorem:
=
+ 
Here, C denotes the hypotenuse length, while A and B signify the lengths of the other two sides of the triangle. We can calculate B's length knowing the hypotenuse is 9 and A is 4.
=
+ 
81= 16+ 
81-16= 
B=
≅8.06
Answer:
La magnitud del EMF es 0.00055 volts
Explanation:
El EMF inducido es proporcional al cambio en el flujo magnético según la ley de Faraday:

Como en nuestro caso hay solo un lazo de alambre, entonces N=1 y obtenemos:

Necesitamos expresar el flujo magnético dada la geometría del problema;
donde A es el área de la bobina que permanece constante con el tiempo, y B es el campo magnético que cambia con el tiempo. Por lo tanto, la ecuación para el EMF se convierte en:
