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yarga
1 month ago
5

Roseanne heated a solution in a beaker as part of a laboratory experiment on energy transfer. After a while, she noticed the liq

uid solution began to circulate within the beaker. What process involving heat transfer did Roseanne observe inside the beaker?
Physics
1 answer:
Ostrovityanka [3.2K]1 month ago
5 0
The answer is water boiling
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A kangaroo jumps to a vertical height of 2.8 m. How long was it in the air before returning to earth
serg [3582]
The kangaroo reaches a maximum vertical altitude of 2.8 m, which can be calculated using the formula 2.8 = 1/2 * 9.8 * t^2. Thus, applying the equation s = ut + 1/2at^2.
8 0
2 months ago
A firecracker breaks up into two pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0 m/
Softa [3030]
O momento total, p = 21.24 kg-m/s
4 0
1 month ago
The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22
inna [3103]
1) The projectile's motion follows
,h(t) = 2+22.5 t-4.9 t^2
In order to determine the velocity, we must compute the derivative of h(t): Next, we will compute the speed at t=2 s and t=4 s: The negative value of the second speed suggests that the projectile has already attained its highest point and is now descending. 2) The maximum height of the projectile occurs when its speed equals zero: Thus, we have And solving yields
t=2.30 s

3) To determine the maximum height, we substitute the time at which the projectile reaches this peak into h(t), specifically t=2.30 s: 4) The time at which the projectile lands is when the height reaches zero; h(t)=0, which leads to This results in a second-degree equation, producing two answers: the negative root can be disregarded as it lacks physical significance; the second root is
t=4.68 s
, which indicates the landing time of the projectile. 5) The moment the projectile impacts the ground corresponds to the velocity at time t=4.68 s:
v(4.68 s)=22.5-9.8\cdot 4.68 =-23.36 m/s
, carrying a negative sign to denote a downward direction.
8 0
1 month ago
Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 4.00. What should be the length of B⃗ so that th
serg [3582]

Answer:

B= \sqrt{65} ≅8.06

Explanation:

Applying the Pythagorean theorem:

C^{2}= A^{2} + B^{2}

Here, C denotes the hypotenuse length, while A and B signify the lengths of the other two sides of the triangle. We can calculate B's length knowing the hypotenuse is 9 and A is 4.

9^{2}=4^{2} + B^{2}

81= 16+ B^{2}

81-16= B^{2}

B= \sqrt{65} ≅8.06

8 0
2 months ago
A loop of wire with cross-sectional area 1 m2 is inserted into a uniform magnetic field with initial strength 1 T. The field is
serg [3582]

Answer:

La magnitud del EMF es 0.00055  volts

Explanation:

El EMF inducido es proporcional al cambio en el flujo magnético según la ley de Faraday:

emf\,=-\,N\, \frac{d\Phi}{dt}

Como en nuestro caso hay solo un lazo de alambre, entonces N=1 y obtenemos:

emf\,=-\,N\, \frac{d\Phi}{dt}

Necesitamos expresar el flujo magnético dada la geometría del problema;

\Phi=B\,\,Adonde A es el área de la bobina que permanece constante con el tiempo, y B es el campo magnético que cambia con el tiempo. Por lo tanto, la ecuación para el EMF se convierte en:

emf\,=-\,N\, \frac{d\Phi}{dt} = \frac{d\Phi}{dt} =-\frac{d\,(B\,A)}{dt} =-\,A\,\frac{d\,(B)}{dt}=- 1\,m^2(2\,\,T/h})= -2\,\,m^2\,T/(3600\,\,s)= -0.00055\,Volts

8 0
1 month ago
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