Response: The updated temperature stands at 10643 K
Clarification:
The combined gas law integrates Boyle's law, Charles's law, and Gay-Lussac's law.
The equation for this law is given by:
where,
= initial gas pressure = 750.0 mm Hg = 0.98 atm (760mmHg=1atm)
= final gas pressure = 3.50 atm
= initial gas volume = 2.00 L
= final gas volume = 20.0 L
= initial gas temperature = 
= final gas temperature =?
Now substituting all the stated values into the equation, we obtain:
Thus, the new temperature results in 10643 K
A negative formation enthalpy indicates that the reaction releases heat during the process.
(C,)
Answer:
Both CaCl2 and CaBr2 consist of elements (bromine and chlorine) from the same group (group 7).
Explanation:
In the periodic table, elements are arranged into groups based on their valence electron count in the outermost shell. Elements in the same group, which possess a similar number of valence electrons, typically exhibit similar chemical behaviors.
Chlorine and Bromine in CaCl2 and CaBr2 belong to group 7, known as HALOGENS, characterized by having 7 valence electrons in their outer shell.
The similarity in properties between CaCl2 and CaBr2 arises because both contain Chlorine and Bromine, leading to analogous reactions and behaviors when interacting with other compounds.
Answer:
Explanation:
We have:
V₁ = 18.5 L
T₁ = 18.5° C = 273 + 18.5 = 291.5 K
V₂ = 19.8 L
T₂ =?
Pressure remains constant
Applying the ideal gas law
<span>Using PV=nRT, which represents a universal constant for any state, we have:
P1V1/n1T1=R
and
P2V2/n2T2=R;
This implies that:
P1V1/n1T1=P2V2/n2T2
Thus we can express it as
V1/n1=V2/n2.
Rearranging yields:
V2=V1 x (n2/n1) = 750 mL x ((0.65+0.35)/(0.65)) = 1200 mL = 1.2 L... with 2 significant figures</span>
