A 0.56 M solution of AlCl₃ is determined to have a concentration of particles of 1.79 M. What is the van't Hoff factor for AlCl₃

Answer:

[Cl⁻] = 0.016M

Explanation:

To begin, we analyze the reaction:

Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓  +  Mg(NO₃)₂(aq)

This indicates a solubility equilibrium, resulting in the formation of lead(II) chloride precipitate. The salt can dissociate as follows:

           PbCl₂(s)  ⇄  Pb²⁺ (aq)  +  2Cl⁻ (aq)     Kps

Initial        x

React       s

Eq          x - s              s                  2s

Given that this is an equilibrium scenario, the Kps serves as the constant (Solubility product):

Kps = s. (2s)²

Kps = 4s³ = 1.7ₓ10⁻⁵

4s³ = 1.7ₓ10⁻⁵

s =  ∛(1.7ₓ10⁻⁵. 1/4)

s = 0.016 M

Answer:

B) Δ[C]/Δt = 3.60x10⁻² M⁻¹s⁻¹ [A] [B]

Explanation:

For the reaction A + B → C

The expression for the reaction's rate is:

Δ[C]/Δt = k [A] [B]

Utilizing the values for [A], [B], and Δ[C]/Δt, multiply [A] by [B] to acquire a value of X and consider Δ[C]/Δt as Y. The slope derived from this linear regression will yield k.

Therefore, the results you should have are:

y = 3.60x10⁻² X

Thus, the reaction's rate is:

B) Δ[C]/Δt = 3.60x10⁻² M⁻¹s⁻¹ [A] [B]

I hope this assists you!

Answer:

Unfavorable reactions include Reaction A and Reaction B.

Favorable coupled reactions: Reactions B with C and Reactions A with C.

Net energy change:

For Reactions B and C: -14.2 kJ/mol

For Reactions A and B: 30.1 kJ/mol

For Reactions A and C: -16.7 kJ/mol

Explanation:

A reaction is considered thermodynamically favorable (or spontaneous) if ΔG is less than 0. Thus, the unfavorable reactions where -ΔG is greater than 0 are:

Reaction A and Reaction B.

In coupling Reaction C with Reaction B and Reaction A, the following equation is obtained:

ATP + fructose-1,6-phosphate ⟶ ADP + fructose-1,6-bisphosphate

ΔG equals 16.3 minus 30.5, resulting in -14.2 kJ/mol.

For the reaction ATP + glucose ⟶ ADP + glucose-6-phosphate, ΔG equals 13.8 minus 30.5, yielding -16.7 kJ/mol.

Overall, the coupled reaction of A and B results in a change of free energy of:

ΔG = 13.8 plus 16.3, which equals 30.1 kJ/mol.

Answer:

The solution's absorbance measures 0.21168.

Explanation:

Provided that,

Wavelength = 500 nm

Molar absorptivity = 252 M⁻¹ cm⁻¹

Moles present = 0.00140

Total solution volume = 500.0 mL

Path length = 3.00 mm

We have to determine the molar concentration

Utilizing the formula for molar concentration

Where N = number of moles

V = volume

Input the values into the formula

Next, we will calculate the solution's absorbance

Using the absorbance formula

Substituting values into the equation

Therefore, the absorbance of the solution is 0.21168.

Answer:

B 1.0 g

Explanation:

Greetings,

Upon analyzing the significant figures, it's evident that 1 g has merely one significant figure. Consequently, among the provided choices, we should go with the one that closely matches this, hence the right answer is B 1.0 g since this measurement fits the required value.

Best wishes.