The ozonolysis of 2,4,4-trimethyl-2-pentene produces a combination of
and
Explanation: In ozonolysis (where a reducing agent like Zn is involved during hydrolysis), a pi bond cleaves to generate ketones or aldehydes.
Ketones arise from the double bond's disubstituted side, whereas aldehydes come from the monosubstituted side of the same bond.
Notably, ozonolysis comprises two steps: (1) the formation of an ozonide, followed by (2) the hydrolysis of the ozonide.
Hydrolysis can transpire with or without a reducing agent. When it occurs without a reducing agent, carboxylic acid, carbon dioxide, or ketones can be produced.
In this case, 2,4,4-trimethyl-2-pentene yields a mixture of and
The reaction process is illustrated below.
The answer is C: hydrogen bonds. Explanation: The surface tension and the capacity for heat storage in water are due to its hydrogen bonds. Water molecules have a strong attraction to one another through hydrogen bonding. These bonds are continuously forming and breaking within water molecules. The result of this hydrogen bonding is surface tension, which allows water to have a greater capacity for heat retention. Consequently, during the night, the temperature on Earth drops much faster than it does for water, as water gradually releases heat, helping maintain a moderate atmospheric temperature at night.
The issue with your setup is that the surface where you placed the drop is contaminated or dirty, preventing it from being wetted by the solution. To fix this, thoroughly clean the surface before applying the drop.
Answer:
[Cl⁻] = 0.016M
Explanation:
To begin, we analyze the reaction:
Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓ + Mg(NO₃)₂(aq)
This indicates a solubility equilibrium, resulting in the formation of lead(II) chloride precipitate. The salt can dissociate as follows:
PbCl₂(s) ⇄ Pb²⁺ (aq) + 2Cl⁻ (aq) Kps
Initial x
React s
Eq x - s s 2s
Given that this is an equilibrium scenario, the Kps serves as the constant (Solubility product):
Kps = s. (2s)²
Kps = 4s³ = 1.7ₓ10⁻⁵
4s³ = 1.7ₓ10⁻⁵
s = ∛(1.7ₓ10⁻⁵. 1/4)
s = 0.016 M
