All categories

10 days ago

You're riding a unicorn at 25 m/s and come to a uniform stop at a red light 20m away. What's your acceleration?

Physics

2 answers:

Ostrovityanka [2.2K]10 days ago

8 0

The result is -15.625 m/s².

Acceleration signifies the alteration of velocity over a specified duration. It can be calculated with this formula:

$a = \dfrac{vf-vi}{t}$

Where:

vf = final velocity

vi = initial velocity

t = time

Let’s examine the information provided in your query:

Initially, the vehicle was traveling at 25 m/s before coming to a halt. Thus, it was in motion and subsequently ceased moving, indicating that the final velocity is 0 m/s.

However, we notice that the problem does not provide a time value. We need to determine the time taken from when it was in motion to when it reached the traffic light located 20 m away.

The time can be calculated using the kinematics equation:

$d = \dfrac{vi+vf}{2} *t$

We derive the equation by substituting the known values first.

$20m = \dfrac{25m/s+0m/s}{2}(t)$

$20m = 12.5m/s{2}(t)$

$\dfrac{20m}{12.5m/s}=t$
$1.6s=t$

The duration from when it was in motion until it stopped is 1.6s. Now we can utilize this in our acceleration calculation.

$a = \dfrac{0m/s-25m/s}{1.6s}$

$a = \dfrac{-25m/s}{1.6s}$

$a = -15.625m/s^{2}$

It is important to note that the acceleration is negative, indicating the vehicle slowed down.

Maru [2.3K]10 days ago

5 0

My acceleration is 15.63 m/s² (decelerating)

To explain:

The formula for acceleration can be expressed as:

Where

vi = initial velocity = 25 m/s $v^{2} _{f} -v^{2} _{i} =2ax$

vf = final velocity = 0

x = distance = 20 m

Substituting values and solving for acceleration "a" results in:

The negative value of acceleration signifies that it is decelerating.

You might be interested in

1. Use Coulomb’s Law (equation below) to calculate the approximate force felt by an electron at point A in the schematic below.

Keith_Richards [2263]

Answer:

Explanation:

The data indicates that point A is located midway between two charges.

To calculate the electric field at point A, we begin with the field produced by charge -Q ( 6e⁻ ) at A:

= 9 x 10⁹ x 6 x 1.6 x 10⁻¹⁹ / (2.5)² x 10⁻⁴

= 13.82 x 10⁻⁶ N/C

This field points towards Q⁻.

A similar field will arise from the charge Q⁺, but it will direct away from Q⁺ toward Q⁻.

To find the resultant field, we add these contributions:

= 2 x 13.82 x 10⁻⁶

= 27.64 x 10⁻⁶ N/C

For the force acting on an electron placed at A:

= charge x field

= 1.6 x 10⁻¹⁹ x 27.64 x 10⁻⁶

= 44.22 x 10⁻²⁵ N

8 0

17 days ago

A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizonta

ValentinkaMS [2425]

No one is going to handle that for a mere 5 points lol.

8 0

1 month ago

d. The force is doubled and the object’s mass is halved? 18. ||| A man pulling an empty wagon causes it to accelerate at 1.4 m/s

Yuliya22 [2438]

Assuming that the mass of the empty wagon is "M," according to Newton's second law, we can derive the following relationships. Given that the empty wagon accelerates at 1.4 m/s², we proceed with this information. If a child weighing three times the mass of the wagon is on it, we can establish the relevant equations.

8 0

8 days ago

A student wishes to determine the heat capacity of a coffee-cup calorimeter. After she mixes 108.7 g of water at 60.2°C with 108

Ostrovityanka [2208]

Answer: The calorimeter's heat capacity is $6.72J/g^oC$