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3 months ago

You're riding a unicorn at 25 m/s and come to a uniform stop at a red light 20m away. What's your acceleration?

Physics

2 answers:

Ostrovityanka [3.2K]3 months ago

8 0

The result is -15.625 m/s².

Acceleration signifies the alteration of velocity over a specified duration. It can be calculated with this formula:

$a = \dfrac{vf-vi}{t}$

Where:

vf = final velocity

vi = initial velocity

t = time

Let’s examine the information provided in your query:

Initially, the vehicle was traveling at 25 m/s before coming to a halt. Thus, it was in motion and subsequently ceased moving, indicating that the final velocity is 0 m/s.

However, we notice that the problem does not provide a time value. We need to determine the time taken from when it was in motion to when it reached the traffic light located 20 m away.

The time can be calculated using the kinematics equation:

$d = \dfrac{vi+vf}{2} *t$

We derive the equation by substituting the known values first.

$20m = \dfrac{25m/s+0m/s}{2}(t)$

$20m = 12.5m/s{2}(t)$

$\dfrac{20m}{12.5m/s}=t$
$1.6s=t$

The duration from when it was in motion until it stopped is 1.6s. Now we can utilize this in our acceleration calculation.

$a = \dfrac{0m/s-25m/s}{1.6s}$

$a = \dfrac{-25m/s}{1.6s}$

$a = -15.625m/s^{2}$

It is important to note that the acceleration is negative, indicating the vehicle slowed down.

Maru [3.3K]3 months ago

5 0

My acceleration is 15.63 m/s² (decelerating)

To explain:

The formula for acceleration can be expressed as:

Where

vi = initial velocity = 25 m/s $v^{2} _{f} -v^{2} _{i} =2ax$

vf = final velocity = 0

x = distance = 20 m

Substituting values and solving for acceleration "a" results in:

The negative value of acceleration signifies that it is decelerating.

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