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Sloan
9 days ago
12

A helicopter is traveling at 86.0 km/h at an angle of 35° to the ground. What is the value of Ax? Round your answer to the neare

st tenth. km/h
Physics
2 answers:
Maru [3.2K]9 days ago
6 0
For the Ax calculation, it’s actually 70.4, while for Ay, it's 49.3.
serg [3.4K]9 days ago
6 0
The result is 70.5 km/h. It seems the question is somewhat vague, but you're inquiring about the x-component of the helicopter's velocity. The x and y components can be calculated using sine and cosine ratios. The sine ratio connects the y-component with the overall velocity as follows: sin(angle) = y-component of velocity / velocity. Meanwhile, the cosine ratio relates the x-component to the velocity: cos(angle) = x-component of velocity / velocity. Given that you have both the angle and the velocity, and need to determine the x-component, you should apply the cosine ratio: cos(35°) = x-component / 86.0 km/h => x-component = 86.0 km/h * cos(35°) = 70.5 km/h.
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An organ pipe open at both ends has a radius of 4.0 cm and a length of 6.0 m. what is the frequency (in hz) of the third harmoni
inna [2995]

When air is forced into the open pipe,

L = \frac{nλ}{2}

where n represents any whole number such as 1,2,3,4, etc., and λ denotes the wavelength of the oscillation

This implies λ=\frac{2L} {n}

It is important to note that n=1 corresponds to the fundamental frequency, n=2 corresponds to the first harmonic, and so forth.

Thus, the third harmonic will be for n=4

With L=6m and n=4, solving for λ yields:

λ=\frac{(2)*(6)}{4} =3m

The connection between frequency (f), sound speed (c), and wavelength (λ) is given by:

c=f.λ or f= \frac{c}{λ}

Therefore, f=\frac{344}{3}

≈115 Hz

8 0
16 days ago
Three moles of an ideal gas with a molar heat capacity at constant volume of 4.9 cal/(mol∙K) and a molar heat capacity at consta
ValentinkaMS [3354]

Answer:

The amount of heat that enters the gas throughout this two-step process totals 120 cal.

Explanation:

Given that,

Moles present = 3

Heat capacity at volume held constant = 4.9 cal/mol.K

Heat capacity at pressure held constant = 6.9 cal/mol.K

Starting temperature = 300 K

Ending temperature = 320 K

We are tasked with determining the heat absorbed by the gas at constant pressure

Employing the heat formula

\Delta H_{1}=nC_{p}\times\Delta T

Substituting the values into the equation

\Delta H_{1}=3\times6.9\times(320-300)

\Delta H_{1}=414\ cal

Next, we calculate the heat absorbed by the gas at constant volume

Using the corresponding heat formula

\Delta H_{1}=nC_{v}\times\Delta T

Insert the values into the formula

\Delta H_{1}=3\times4.9\times(300-320)

\Delta H_{1}=-294\ cal

Now, it's necessary to evaluate the total heat flow into the gas during both steps

Using the total heat formula

\Delta H_{T}=\Delta H_{1}+\Delta H_{2}

\Delta H_{T}=414-294

\Delta H_{T}=120\ cal

Thus, the heat that transfers into the gas throughout this two-step process amounts to 120 cal.

7 0
1 month ago
A good quarterback can throw a football at 27 m/s (about 60 mph). If we assume that the ball is caught at the same height from w
ValentinkaMS [3354]

Response:

The ball remained airborne for 3.896 seconds

Explanation:

Given that

g = 9.8 m/s², representing gravitational acceleration,

If the angle of launch is 45°, the horizontal range will be maximized.

Both horizontal and vertical launch velocities are equal, each equating to

v_h  =  v cos θ

v_h  =  27 × cos 45°

         = 19.09 m/s.

The duration to reach maximum height is half of the flight time.

v = u + at   ∵ v = 0 (at maximum height)

19.09 - 9.8 t₁ = 0

t₁ = 1.948 s

The total time in the air equals twice the time to reach maximum height

2 t₁ = 3.896 s

The horizontal distance covered is

D = v × t

D = 3.896×19.09

   = 74.375 m

The ball was in the air for 3.896 seconds

8 0
19 days ago
The plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 80.0 nC. The plates are in va
serg [3477]

Answer:

10000 V

0.00225988700565 m²

8\times 10^{-12}\ F

Explanation:

E = Electric field = 4\times 10^6\ V/m

d = Distance = 2.5 mm

Q = Charge = 80 nC

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

The potential difference is calculated as

V=Ed\\\Rightarrow V=4\times 10^6\times 2.5\times 10^{-3}\\\Rightarrow V=10000\ V

The potential difference across the plates amounts to 10000 V

Area is determined by

A=\dfrac{Q}{\epsilon_0E}\\\Rightarrow A=\dfrac{80\times 10^{-9}}{8.85\times 10^{-12}\times 4\times 10^6}\\\Rightarrow A=0.00225988700565\ m^2

The area of each plate measures 0.00225988700565 m²

Capacitance is determined by

C=\dfrac{\epsilon_0A}{d}\\\Rightarrow C=\dfrac{8.85\times 10^{-12}\times 0.00225988700565}{2.5\times 10^{-3}}\\\Rightarrow C=8\times 10^{-12}\ F

The capacitance is 8\times 10^{-12}\ F

4 0
15 days ago
A solid metal sphere of diameter D is spinning in a gravity-free region of space with an angular velocity of ωi. The sphere is s
ValentinkaMS [3354]

Answer:

0.6

Explanation:

The formula for the volume of a sphere is \frac{4}{3} \pi (\frac{D}{2})^3

Thus \pi * r^2 * (\frac{D}{2} ) = \frac{4}{3} \pi (\frac{D}{2})^3

The radius of the disk is 1.15(\frac{ D}{2} )

Applying angular momentum conservation;

The M_i of the sphere = \frac{2}{5} m \frac{D}{2}^2

M_i of the disk = m*\frac{ \frac{1.15*D}{2}^2 }{2}

\frac{wd}{ws} = \frac{\frac{2}{5}m * \frac{D}{2}^2}{ m * \frac{(\frac{`.`5*D}{2})^2 }{2} }

= 0.6

5 0
1 month ago
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