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DanielleElmas
1 month ago
13

When 10 g of diethyl ether is converted to vapor at its boiling point, about how much heat is absorbed? (c4h10o, δhvap = 15.7 kj

/mol, boiling point: 34.6°c) 0.2 kj 3 kj .01 kj 2 j?
Chemistry
1 answer:
Alekssandra [3K]1 month ago
5 0
ΔH = 3KJ. La chaleur totale absorbée représente l'énergie totale du processus, et cela se mesure en termes d'enthalpie. ΔH = q + ΔHvap, où q représente la chaleur nécessaire pour élever la température du diéthyl-éther. Supposons que la température initiale soit ambiante (25ºC = 298 K), alors q = 10g x 2.261 J/gK x (310 K - 298 K) = 271,32 J = 0,3 kJ. Ensuite, ΔHvap = 10g C4H10O x (1 mol C4H10O / 74,12 g C4H10O) x (15,7 KJ / 1 mol C4H10O) = 2,12 KJ. Ainsi, ΔH = 2,5 KJ ≈ 3 KJ.
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Explanation:

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3s^23p_x^23p_y^23p_z^1  = 7

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Approximately 220 million tires are discarded in the U.S. each year. These tires present a disposal problem because they take up
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A total of 2667 tires are required to satisfy the annual power needs of ten homes.

Explanation:

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E_{out} = \eta \cdot E_{in}

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E_{in} - Energy released from burning, measured in kilowatt-hours.

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n = \frac{(10\,homes)\cdot \left(10000\,\frac{kWh}{home} \right)}{37.5\,\frac{kWh}{tire} }

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<span>Some solutions demonstrate colligative properties, which rely on the quantity of solute in a solvent. To find the elevation in boiling point, we use the formula:

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