Respuesta:
0.16 M
Explicación:
Teniendo en cuenta:
O sea,
Dado que:
Para 
:
Molaridad = 0.200 M
Volumen = 20.0 mL
Convierte mL a L:
1 mL = 10⁻³ L
Entonces, volumen = 20.0×10⁻³ L
Los moles de son:
Moles de = 0.004 moles
Para 
:
Molaridad = 0.400 M
Volumen = 30.0 mL
Convertimos mL a L:
1 mL = 10⁻³ L
Volumen = 30.0×10⁻³ L
Entonces, los moles de son:
Moles de = 0.012 moles
Según la reacción:
1 mol de reacciona con 1 mol de
Por lo tanto,
0.012 mol de reacciona con 0.012 mol de
Moles disponibles de = 0.004 mol
El reactivo limitante es el que está en menor cantidad, entonces es el limitante (0.004 < 0.012).
La formación del producto depende del reactivo limitante, así que,
1 mol de reacciona con 1 mol de y produce 1 mol de 
0.004 mol de reacciona con 0.004 mol de y genera 0.004 mol de
Los moles restantes de son: 0.012 - 0.004 = 0.008 mol
El volumen total es 20 + 30 mL = 50 mL = 0.050 L
Por lo que la concentración del ion bario, 
, después de la reacción es:
Answer:
Explanation:
Given data:
Initial temperature T₁ = 25.2°C = 298.2K
Initial pressure P₁ = 0.6atm
Final temperature = 72.4°C = 345.4K
What we need to find:
Final pressure = ?
To determine this, we apply a modified version of the combined gas law with constant volume. This simplifies our calculations to:
Here, P and T signify pressure and temperatures, 1 refers to initial and 2 to final temperatures.
Now we can substitute the known variables:
P₂ = 0.7atm
This procedure entails diluting the 12 molar HCl. To decrease the concentration, we must create an equation to determine how much of the 12M is needed for the 3.5M solution.
12 moles HCl 3.5 moles HCl
——————— = ———————
1 Liter of Soln ‘x’ Liters of Soln
Note that the ratio of 12 moles over 1 liter corresponds to 12 molar; thus, we maintain the original concentration of the HCl. By equating it to the 3.5 over ‘x’, we are still preserving the concentration.
After computation, we determine ‘x’ to be 0.292. This value indicates that within 0.292 liters of our 12 M HCl solution, there are 3.5 moles of HCl. Yet, we are not finished.
0.292 liters of 12 M HCl can create 1 liter of 3.5 M HCl, but the inquiry demands 1.5 liters. To achieve this, multiply 0.292 liters by 1.5, resulting in 0.4375, which denotes the quantity of 12 M HCl necessary to prepare a 1500 mL 3.5 M HCl solution.
Answer:
Explanation:
The oxidation state corresponds to the charge of each atomic ion. An increase indicates oxidation of the element while a decrease reflects reduction of the element.
2AgCl+Zn⟶2Ag+ZnCl2
Zinc undergoes oxidation, while Ag experiences reduction.
Ag⁺ changes to Ag (oxidation state decreases), thus Ag is reduced.
Zn alters to Zn⁺² (oxidation state increases), hence Zn is oxidized.
4NH₃+3O₂⟶2N₂+6H₂O
The oxidation state of nitrogen in ammonia is -3
whereas it is zero in elemental nitrogen.
An increase in the oxidation state indicates nitrogen is oxidized.
The oxidation state of oxygen is zero when in molecular oxygen and -2 when in water. Therefore, the oxidation state decreases, indicating oxidation is reduced.
Fe₂O₃+2Al⟶Al₂O₃+2Fe
The oxidation state of Fe in Fe₂O₃ is +3, switching to zero in Fe, so iron is reduced.
Aluminum's oxidation state is zero in Al, rising to +3 in Al₂O₃, indicating it is oxidized.
The stronger the attraction between elements, the shorter the bond length becomes; conversely, a weaker attraction results in a longer bond length. This attraction arises from differences in their electronegativities, which is the capacity of an element to draw electrons toward itself. According to periodic trends, electronegativity rises as you move left to right and bottom to top on the periodic table. Therefore, the order from the most electronegative to the least is: Cl > Br > I. As a result, the sequence by bond length from shortest to longest is: C-Cl > C-Br > C-I.
