Answer:
1.5
Explanation:
It is given that:
Compound A and B originate from Sulfur + Oxygen.
Compound A:
6g sulfur + 5.99g Oxygen
Compound B:
8.6g sulfur + 12.88g oxygen
By comparing the ratios:
Compound A:
S: O = 6.00: 5.99
S/0 = 6.0g S / 5.99g O
Compound B:
S: O = 8.60: 12.88
S / O = 8.60g S / 12.88g O
The mass ratio of A and that of B
(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)
(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)
(6 × 12.88) / (5.99 × 8.60)
= 77.28 / 51.514
= 1.50017
= 1.5
To determine the mass of the lead piece, we use the following equation: Q(heat) = mC delta T, where Q equals 78.0 j, M is the mass we want to find, C is the specific heat capacity (0.130 j/g/C), and delta T shows the temperature difference, set at 9.0 c. Rearranging the formula to solve for M gives us M = Q / c delta T. By substituting in the values, we conclude that M = 78.0 j / (0.130 j/g/C * 9.0 C), calculating this gives us a mass of 66.7 g of lead.
Ca3(PO4)2 is the correct formula.
